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3241004551 [841]
3 years ago
5

Hypothesis Bob wants to see if different smells travel at the same speed. He sprays a can of hairspray, peppermint air freshener

, and insect repellant at the same time. Six friends stand around him in a large circle, five feet from the center of the circle where Bob stood
Chemistry
1 answer:
Leya [2.2K]3 years ago
4 0

Answer:

I dont think that different smells travel at the same speed because, if one of the different sprays are heavier than another spray, it will be slower.

Explanation:

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1. How many molecules of barium hydroxide, Ba(OH)2 are there in 21.9 grams of
vladimir2022 [97]

Answer: 7.7\times 10^{22} molecules of Ba(OH)_2

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{21.9g}{171g/mol}=0.128moles

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0.128 mole of Ba(OH)_2 contains =  \frac{6.023\times 10^{23}}{1}\times 0.128=7.71\times 10^{22} molecules

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3 0
3 years ago
Find the volume of 0.130M sulfuric acid necessary to react completely with 65.9g sodium hydroxide
xxTIMURxx [149]

The volume of the 0.130 M sulfuric acid, H₂SO₄ required to react completely with 65.9 g sodium hydroxide, NaOH is 6.34 L

  • We'll begin by calculating the number of mole of in 65.9 g sodium hydroxide, NaOH. This can be obtained as follow:

Mass of NaOH = 65.9 g

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

<h3>Mole of NaOH =?</h3>

Mole = mass / molar mass

Mole of NaOH = 65.9 / 40

<h3>Mole of NaOH = 1.6475 mole</h3>

  • Next, we shall determine the number of mole of H₂SO₄ needed to react with 1.6475 mole of NaOH. This can be obtained as follow:

2NaOH + H₂SO₄ —> Na₂SO₄ + 2H₂O

From the balanced equation above,

2 moles of NaOH reacted with 1 mole of H₂SO₄.

Therefore,

1.6475 mole of NaOH will react with = \frac{1.6475}{2} \\\\ = 0.82375 mole of H₂SO₄.

  • Finally, we shall determine the volume of 0.130 M sulfuric acid, H₂SO₄ required for the reaction.

Molarity of H₂SO₄ = 0.130 M

Mole of H₂SO₄ = 0.82375 mole

<h3>Volume of H₂SO₄ =? </h3>

Volume = mole / Molarity

Volume of H₂SO₄ = 0.82375 / 0.130

<h3>Volume of H₂SO₄ = 6.34 L </h3>

Therefore, the volume of the 0.130 M sulfuric acid, H₂SO₄ required for the reaction is 6.34 L

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