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3241004551 [841]
3 years ago
5

Hypothesis Bob wants to see if different smells travel at the same speed. He sprays a can of hairspray, peppermint air freshener

, and insect repellant at the same time. Six friends stand around him in a large circle, five feet from the center of the circle where Bob stood
Chemistry
1 answer:
Leya [2.2K]3 years ago
4 0

Answer:

I dont think that different smells travel at the same speed because, if one of the different sprays are heavier than another spray, it will be slower.

Explanation:

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BabaBlast [244]
Polar liquids have both negative and positive ends.
3 0
4 years ago
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How many total atoms are in 0.530 g of P2O5/12131141/dc2696ff?utm_source=registration
Lyrx [107]
In order to calculate the number of atoms present in 0.53 grams of P₂O₅, first calculate the number of moles for given mass.

As, Moles is given as,

                             Moles  =  Mass / M.mass

                             Moles  =  0.53 g ÷ 283.88 g.mol⁻¹

                             Moles  =  0.00186 moles

Now calculate the number of Molecules present in calculated moles of P₂O₅.

As,
                        1 Mole of P₂O₅ contains  =  6.022 × 10²³ Molecules
So,
             0.00186 Moles of P₂O₅ contain  =  X Molecules

Solving for X,
                        X  =  (0.00186 mol × 6.022 × 10²³ Molecules) ÷ 1 mol

                        X  =  1.12 × 10²¹ Molecules

Also, in P₂O₅ there are 7 atoms, in 1.12 × 10²¹ Molecules there will be.....

                            = 1.12 × 10²¹ × 7

                            =  7.84 × 10²¹ Atoms
Result:
            
7.84 × 10²¹ Atoms are present in 0.53 grams of P₂O₅.
8 0
3 years ago
Octane has a density of .692 g/mL at 20 degrees C. How many grams of O2 are required to burn 19.0 gal of C8H18?
madreJ [45]
3.64 hope that helps you 
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3 years ago
A compound decomposes by a first-order process. What is the half-life of the compound if 25.0% of the compound decomposes in 60.
amid [387]

Answer : The half-life of the compound is, 145 years.

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time passed by the sample  = 60.0 min

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process = 100 - 25 = 75 g

Now put all the given values in above equation, we get

k=\frac{2.303}{60.0}\log\frac{100g}{75g}

k=4.79\times 10^{-3}\text{ years}^{-1}

Now we have to calculate the half-life of the compound.

k=\frac{0.693}{t_{1/2}}

4.79\times 10^{-3}\text{ years}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=144.676\text{ years}\approx 145\text{ years}

Therefore, the half-life of the compound is, 145 years.

8 0
4 years ago
What does n equal for one shell ...... Hiiiiiiiiiiiiiiiiii<br><br>A. 2<br><br>B.8<br><br>C.14
andrew-mc [135]

Answer:

B

Explanation:

the equal of the shell is b

5 0
3 years ago
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