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SVETLANKA909090 [29]
3 years ago
5

The fall of the Zhou dynasty began a period referred to as __________.

Mathematics
3 answers:
charle [14.2K]3 years ago
8 0
The fall of the Zhou dynasty began a period referred to as the Warring States period. The Warring states period consisted of essentially seven states engaging in war with each other. The Zhou Dynasty lasted longer than any other Chinese dynasty, but the power of the dynasty lasted for a shorter period of time than their reign. 
vladimir1956 [14]3 years ago
5 0

Answer:

Warring states period! Got it right on edge!

Step-by-step explanation:

malachi 11342 years ago
0 0

The dang answer is c

You might be interested in
the midpoint of [KL] is (-8, 1). one endpoint is K(-6, 5). find the coordinates of the other endpoint L
ExtremeBDS [4]

the correct question is

The midpoint of kl is m(–8, 1). one endpoint is k(–6, 5). find the coordinates of the other endpoint l.


we know that

the formula of midpoint is

Xm=(x1+x2)/2----> 2*Xm=x1+x2------> x2=2*Xm-x1

Ym=(y1+y2)/2----> 2*Ym=y1+y2------> y2=2*Ym-y1


let

(x1,y1)-------> (–6, 5).

(Xm,Ym)-----> (-8,1)


find (x2,y2)

x2=2*Xm-x1-----> 2*(-8)-(-6)----> -10

 y2=2*Ym-y1----> 2*(1)-5-----> -3


the point l is (-10,-3)




3 0
2 years ago
3. Which statement below is the conclusion
Marrrta [24]

Answer:

a number hahah

Step-by-step explanation:

as i guess i think haha

8 0
2 years ago
Read 2 more answers
find the equation of a circle which passes through the point (2,-2) and (3,4) and whose centre lies on the line x+y=2
Nadusha1986 [10]

Answer:

Equation of the circle

(x - 0.7)² + (y - 1.3)² = 12.58

Step-by-step explanation:

The formula for the equation of a circle is given as:

(x - a)² + (y - b)² = r²,

where(a, b) is the center of the circle and r = radius of the circle.

a) We are told in the question that the equation of the circle passes through point(2, -2)

Hence,

Substituting 2 for x and -2 for y in the equation of the circle.

(x - a)² + (y - b)² = r²

(2 - a)² +(-2 - b)² = r²

Expanding the bracket

(2 - a) (2 - a) + (-2 - b)(-2 - b) = r²

4 - 2a - 2a +a² +4 +2b +2b +b² = r²

4 - 4a + a² + 4 + 4b + b² = r²

a² + b² -4a + 4b + 4 + 4 = r²

a² + b² -4a + 4b + 8 = r²............Equation 1

We are also told that the equation of the circle also passes through point (3,4) also, where 3 = x and 4 = y

Hence,

Substituting 3 for x and 4 for y in the equation of the circle.

(x - a)² + (y - b)² = r²

(3 - a)² +(4 - b)² = r²

Expanding the bracket

(3 - a) (3 - a) + (4 - b)(4- b) = r²

9 - 3a - 3a +a² +16 -4b -4b +b² = r²

9 -6a + a² + 16 -8b + b² = r²

a² + b² -6a -8b + 9 + 16 = r²

a² + b² -6a -8b + 25 = r²..........Equation 2

The next step would be to subtract Equation 1 from Equation 2

a² + b² -4a + 4b + 8 - (a² + b² -6a -8b + 25) = r² - r²

a² + b² -4a + 4b + 8 - a² - b² +6a +8b - -25= r² - r²

Collecting like terms

a² - a² + b² - b² - 4a + 6a + 4b + 8b +8- 25 = 0

2a + 12b -17 = 0

2a + 12b = 17...........Equation 3

Step 2

We are going to have to find the values of a and b in other to get our equation of the circle.

Since the center of the circle(a, b) lies on x + y = 2

Therefore, we have

a + b = 2

a = 2 - b

2a + 12b = 17 ..........Equation 3

Substituting 2 - b for a in

2(2 - b) + 12b = 17

4 - 2b + 12b = 17

4 + 10b = 17

10b = 17 - 4

10b = 13

b = 13/10

b = 1.3

Substituting 1.3 for b in

a + b = 2

a + 1.3 = 2

a = 2 - 1.3

a = 0.7

hence, a = 0.7, b = 1.3

Step 3

We have to find the value of r using points (2, -2)

(x - a)² + (y - b)² = r²

Where x = 2 and y = -2

(-2 - 0.7)² + (-2 - 1.3)² = r²

(-2.7)² + (-3.3)² = r²

1.69 + 10.89 = r²

r² = 12.58

r = √12.58 = 3.55

Step 4

The formula for the equation of a circle is given as:

(x - a)² + (y - b)² = r²,

where(a, b) is the center of the circle and r = radius of the circle

a = 0.7

b = 1.3

r² = 12.58

Equation of the circle =

(x - 0.7)² + (y - 1.3)² = 12.58

7 0
3 years ago
Which expression is equivalent to one over threep + 15? one over three(p + 45) one over three(p + 5) 3(p + 45) 3(p + 5)
elena-s [515]

Answer:

\large\boxed{\dfrac{1}{3p+15}=\dfrac{1}{3(p+5)}}

Step-by-step explanation:

"one over threep + 15":

\dfrac{1}{3p+15}=\dfrac{1}{(3)(p)+(3)(5)}=\dfrac{1}{(3)(p+5)}=\dfrac{1}{3(p+5)}

5 0
3 years ago
Read 2 more answers
What is the inverse equation for h(x) = 2log(x-3) ?
marshall27 [118]

Given the function:

h(x)=2log\left(x-3\right)

To find its inverse:

\begin{gathered} y=2log\left(x-3\right) \\ x=2log\left(y-3\right) \end{gathered}

solving for y:

\frac{x}{2}=log(y-3)\begin{gathered} 10^{\frac{x}{2}}=y-3 \\  \\ 10^{\frac{x}{2}}+3=y \end{gathered}

ANSWER

h^^{-1}(x)=10^{\frac{x}{2}}+3

8 0
1 year ago
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