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Bogdan [553]
2 years ago
11

Mr miles for $22.50 on rides at the Carnival for his grandchildren each ride costs $1.25 right inside of an equation to find how

many rides are you paid for in all
Mathematics
2 answers:
timurjin [86]2 years ago
6 0

Answer:

22.50/1.25=18

Step-by-step explanation:

if he paid 22.50 in total and each ride cost 1.25 then you would just have to do 22.50 divided by 1.25 which would get you 18

Inga [223]2 years ago
5 0

Step-by-step explanation:

hfghYdFuszutdyizruzurzfzf the world of the world of devil fush of a place in the blanks of the day I extend r e e e tiki torches and different the se class 9th March of a diagram to and different the

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a gas station sells regular gas for $2.10 per gallon and premium gas for $2.90 a gallon. at the end of a business day 280 gallon
insens350 [35]

200 gallons of regular gas and 80 gallons of premium gas were sold.

Let the amount of regular gas sold be x gallons. So, the amount of premium gas sold will be (280 - x).

Now, forming the equation using the given information, to find the amount of each type of gallon.

Equation -

2.10x + 2.90(280 - x) = 652

Performing multiplication with values inside bracket in Left Hand Side

2.10x + 812 - 2.90x = 652

Rewriting the equation -

812 - 652 = 2.90x - 2.10x

Performing subtraction

160  = 0.8x

Rewriting the equation according to x

x = 160÷0.8

Performing division to find the value of x

x = 200

So, 200 gallons of regular gas was sold.

Amount of premium gas sold = 280 - 200

Performing subtraction

Amount of premium gas sold = 80 gallons

Hence, 200 gallons of regular gas and 80 gallons of premium gas was sold.

Learn more about problems on gas -

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4 0
1 year ago
Help ASAP Please check to see if I have the last part correct. Thanks
7nadin3 [17]
<span>In 10 repetitions, there was an instance where 3 or more out of 5 free throw missed. So the probability of her missing 3 or more out of 5 free throw is 0/10=0% or 0.0%. I</span>t appears that your answer of 0% is correct given your experiment.
3 0
3 years ago
Read 2 more answers
Write an algebraic expression for the given quantity. Let x represent the unknown value.
Lelechka [254]

Answer:

Step-by-step explanation:

There is no equal sign.

1/2 x - 5*x

is all there is.

7 0
2 years ago
Which expression represents the gcf of 154 and 196.
saveliy_v [14]
Answer=A

To find the gcf, we need to factor each number.

154=2*7*11

196=2*2*7*7

The number have a factor of 2 and a factor of 7 in common, so...


GCF=2*7
3 0
3 years ago
Read 2 more answers
If f(x) = 9x10 tan−1x, find f '(x).
djverab [1.8K]

Answer:

\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)  

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = 9x^{10} \tan^{-1}(x)

<u>Step 2: Differentiate</u>

  1. [Function] Derivative Rule [Product Rule]:                                                   \displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  2. Rewrite [Derivative Property - Multiplied Constant]:                                  \displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  3. Basic Power Rule:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]
  4. Arctrig Derivative:                                                                                         \displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0
2 years ago
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