Answer:
Refer below
Step-by-step explanation:
a) a and b are the lower and higher values of the interval for which uniform distribution is defined.
Here a= 6 and b =10
b) Mean of the uniform distribution= (a+b)/2 = (6+10)/2 =8
Or int x (1/4) dx = x^2/8 = 8
c) Variance of the uniform distribution = (b^2-a^2)/12 = (100-64)/12
= 36/12 =3
Std dev = sq rt of 3 = 1.732
d) To find total area
PDF of the distribution = 1/(b-a) = 1/4, 6<x<10
Area = \int 6 to 10 of 1/4 dx
= x/4
Subtitute limits
= (10-6)/4 =1
So total area = 1
d)P(X>7) = int 7 to 10 of 1/4 dx = 3/4
e) P(7<x<9) = Int 7 to 9 of 1/4 dx = 2/4 = 1/2
Answer:
It is a money market account. So answer A.
Step-by-step explanation:
The answers are the following
1. B
2. A
3. B
4. A
Since A (area of circle = C) is given = 148
Where we assume:
Y represents radius of the circle (r)
X represents diameter of the circle (D)
Pi (π) = 3.14
A = 2 * π * y
148 = 2 * 3.14 * y
148 = 6.28 * y
y = 148/6.28
So, y = 23.56
D = 2 * y
D = 2 * 23.56
So, D = 47.12
Assume A is unknown (not given as 148)
A = π * y^2
A = 3.14 * (23.56)^2
A = 3.14 * 47.12
So, A = 147.95 (approx. A = 148)
