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RoseWind [281]
3 years ago
12

What mass of HCL, in grams, is required to react with 0.610 g of al(oh)3 ?

Chemistry
1 answer:
kompoz [17]3 years ago
3 0

Answer: 0.8541 grams of HCl will be required.

Explanation: Moles can be calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of Al(OH)_3 = 0.610 g

Molar mass of Al(OH)_3 = 78 g/mol

\text{Number of moles}=\frac{0.610g}{78g/mol}

Number of moles of Al(OH)_3 = 0.0078 moles

The reaction between Al(OH)_3 and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.

Chemical equation for the above reaction follows:

Al(OH)_3+3HCl\rightarrow AlCl_3+3H_2O

By Stoichiometry,

1 mole of  Al(OH)_3 reacts with 3 moles of HCl

So, 0.0078 moles of Al(OH)_3 will react with \frac{3}{1}\times 0.0078 = 0.0234 moles

Mass of HCl is calculated by using the mole formula, we get

Molar mass of HCl = 36.5 g/mol

Putting values in the equation, we get

0.0234moles=\frac{\text{Given mass}}{36.5g/mol}

Mass of HCl required will be = 0.8541 grams

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The buildup of sediment in which a river empties right into a slow-transferring or non transferring frame of water is referred to as a Delta.

<h3>What is Delta ?</h3>

Deltas are wetlands that shape as rivers empty their water and sediment into some other frame of water, together with an ocean, lake, or some other river.

A form of soil made nearly completely of windblown sediment is referred to as Loess.

The natural count number in soil comes from decaying flora and animals and their waste products.

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A form of soil referred to as peat is maximum probably to shape in a/an Coastal surroundings in Tropical placing.

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The Richness of nutrients from soil is not unusualplace in moist environments, like rain forests.

Quartz-wealthy determine cloth results in the improvement of Sandy soils.

The layers of soil composed specifically of natural count number are referred to as the O and A horizon.

A layer of soil wherein clay, iron, and different factors from the overlying soil accumulates is referred to as the B horizon, or subsoil.

  • Delta is stated to be a frame of sediments deposited whilst a river flows into a status water, together with the ocean or a lake.

  • Loess are wind blown deposits of silts and clay composed of quartz, feldspar and different minerals . Loess dominantly have excessive porosity.

  • Organic subjects compose specifically of stays of animal and flora . After this flora and animals dies they shape natural count number that provides to soil vitamins.

  • Clayey soil represent very tiny debris which have a bad draining cappotential because of it tiny bad spaces .

  • Tropical placing in a coastal surroundings affords the important environments for soils like peat to shape . It has plentiful of plant stays . Moreover peat is the primary degree of coal formation, containing wet and unconsolidated plant substances.

  • Minerals part of what help withinside the improvement of the soil .And additionally it is carried right all the way down to the earth with the aid of using water thru a procedure referred to as Leaching.

  • Richness of nutrient are not unusualplace in tropical surroundings which are moist and help plentiful life.

  • Sandy soil are fashioned from dad and mom substances containing minerals together with feldspar and quartz.

  • Horizon O and A are referred to as topsoil and are specifically compose of animal and flora stays and big quantity of minerals.

  • The subsoil or B Horizons consists of mineral together with irons , clay minerals because of percolation from the pinnacle soils and it has a tendency to build up here(subsoil).

Learn more about Horizon here ;

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There are two isotopes of an unknown element, X-19 and X-21. The abundance of X-19 is 14.55%. A weighted average uses the percen
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Answer:

2.765amu is the contribution of the X-19 isotope to the weighted average

Explanation:

The average molar mass is defined as the sum of the molar mass of each isotope times its abundance. For the unknown element X that has 2 isotopes the weighted average is defined as:

X = Mass X-19 * Abundance X-19 + MassX-21 * Abundance X-21

The contribution of the X-19 isotope is its mass (19.00 amu) times its abundance (14.55% = 0.1455). That is:

19.00amu * 0.1455 =

2.765amu is the contribution of the X-19 isotope to the weighted average

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