Answer:
In order to rinse the system of exhaled CO2 and meet the inspiratory flow rate requirements of infants placed on B-CPAP, the flow rate of humidified gas should be set at:
A. 16 to 20 L/minute
B. 6 to10 L/minute
C. at least 15 L/minute
D. 11 to 15 L/minute
B. 6 to10 L/minute
Explanation:
Bubble CPAP is a non-invasive, external ventilation technique used for newborn babies with infant respiratory distress syndrome (IRDS). Continuous positive airway pressure (CPAP) is given to a spontaneously breathing newborn baby to preserve lung volumes during expiration
Based on the balanced chemical reaction presented above, every mole of magnesium (Mg) yields one mole of diatomic hydrogen (H2). When converted to masses, every 24.3 grams of magnesium yields 2 grams of hydrogen.
From the given, there are 20 grams of magnesium available for the reaction. With this amount, the expected yield of hydrogen is 1.646 grams. To calculate the percent yield, divide the actual yield to the hypothetical yield.
*The case is impossible because the actual yield is greater than the theoretical yield.
If we assume that there had been a typographical error and that the actual yield is 0.7 grams instead of 1.7 grams, the percent yield becomes 42.5%. Thus, the answer is letter E.
Answer:
pOH = 9.
Explanation:
The inverse relationship between the pH and pOH of any given solution can be written as:
pH = 14 - pOH
Or conversely:
pOH = 14 - pH
With the above information in mind we can <u>use the given pH to calculate the pOH</u>:
pOH = 14 - pH
pOH = 14 - 5
pOH = 9
Thus, black coffee has a pOH of 9.
Hi there!
Your correct answer will be 12.2 cm³.
This is how you get there:
1 mL = 1 cm³
With this one conversion factor, you can extrapolate the final answer. When you add the granite to the water, which is filled to 25.0 mL, the water level then moves to 37.2 mL. If you subtract the before volume from the volume after, you will get an answer of 12.2 mL. Then use the conversion factor and, voila! 12.2 cm³
I hope this helps!
Brady
Answer:
Moles NH₃: 0.0593
0.104 moles of N₂ remain
Final pressure: 0.163atm
Explanation:
The reaction of nitrogen with hydrogen to produce ammonia is:
N₂ + 3 H₂ → 2 NH₃
Using PV = nRT, moles of N₂ and H₂ are:
N₂: 1atmₓ3.0L / 0.082atmL/molKₓ273K = 0.134 moles of N₂
H₂: 1atmₓ2.0L / 0.082atmL/molKₓ273K = 0.089 moles of H₂
The complete reaction of N₂ requires:
0.134 moles of N₂ × (3 moles H₂ / 1 mole N₂) = <em>0.402 moles H₂</em>
That means limiting reactant is H₂. And moles of NH₃ produced are:
0.089 moles of H₂ × (2 moles NH₃ / 3 mole H₂) = <em>0.0593 moles NH₃</em>
Moles of N₂ remain are:
0.134 moles of N₂ - (0.089 moles of H₂ × (1 moles N₂ / 3 mole H₂)) = <em>0.104 moles of N₂</em>
And final pressure is:
P = nRT / V
P = (0.104mol + 0.0593mol)×0.082atmL/molK×273K / 5.0L
<em>P = 0.163atm</em>
