Answer:
The pressure the gas will have if the pressure is initially 1.50 atm at 22.0 ° C and the temperature changes at 11.0 ° C is 1.44 atm (option D)
Explanation:
Gay Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move more rapidly. Then the number of collisions against the walls increases, that is, the pressure increases. That is, the gas pressure is directly proportional to its temperature.
Gay-Lussac's law can be expressed mathematically as follows:

Where P = pressure, T = temperature, K = Constant
You have a gas that is at a pressure P1 and at a temperature T1. When the temperature varies to a new T2 value, then the pressure will change to P2, and then:

In this case:
- P1= 1.50 atm
- T1= 22 °C= 295 °K (being 0°C= 273 °K)
- P2= ?
- T2= 11 °C= 284 K
Replacing:

Solving:

P2=1.44 atm
<u><em>The pressure the gas will have if the pressure is initially 1.50 atm at 22.0 ° C and the temperature changes at 11.0 ° C is 1.44 atm (option D)</em></u>
F(x)=-1/x
g(x)=√(3x-9)
Domain of (f/g)(x): ??
1We find out the domain of f(x):
f(x) is a rational function, therefore can take real values if the denominator is not ("0"), therefore the domain of f, will be all values excpet "0"
Domain of f: (-∞,0)U(0,+∞);
o
----------------------------------------------O-------------------------------------------
←-------- -∞ +∞ ----------→
g(x) is a radical square root function, therefore the radicand have to be greater than o equal to "0"
3x-9≥0
3x≥9
x≥3
3
.........................................................Ф--------------------------------
←--------- - ∞ +∞ -----------→
(f/g)(x) = (-1/x) / (√(3x-9)) is a rational function with a square root in the denominator,also the square root don´t take the value of "0";
Therefore:
3x-9>0
3x>9
x>3
The domain of the function (f/g)(x) only can take the values found in all three domains at once.
3
............................................................0---------------------------------
←--------- -∞ +∞-------------→
Answer: (3,+∞)
<span>0 K on the Kelvin scale, which is absolute temperature scale; and –273.15 degrees Celsius on the Celsius scale, thus world wide has come to an agreement saying absolute zero is precisely. </span>
Answer:
storm runoff
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It is translational motion. i know because i found it on this site. its verified too, have a nice day