<span> the electron configuration for the manganese atom [Ne]3s</span>²
Answer:
K=1.61×10−19 J
Explanation:
In the question data given is as follows:
Wavelength of the is given as light (λ)=233 nm
while the worrk-function of the titanium given as (ϕ)=6.93×10−19 J
but for the energy imparted due to the light will now be
E=hcλE, then
E=hcλE=(6.63×10−34)(3×108) / 233×10−9
E=8.536×10−19 J
Now, the energy imparted is given by
E= ϕ + K
8.536×10−19= (6.93×10−19) + K
K=1.61×10−19 J
Then,
K is the kinetic energy of the electrons
Answer:
Butan-2-one
Explanation:
1. 1700 cm⁻¹
A strong peak near 1700 cm⁻¹ is almost certainly a carbonyl (C=O) group.
2. Triplet-quartet
A triplet-quartet pattern indicates an ethyl group.
The 2H quartet is a CH₂ adjacent to a CH₃. The peak normally occurs at δ 1.3, but it is shifted 1.2 ppm downfield to δ 2.47 by an adjacent C=O group.
The 3H triplet at δ 1.05 is the methyl group. It, too, is shifted downfield from its normal position at δ 0.9. The effect is smaller, because the methyl group is further from the carbonyl.
3. 3H(s) at δ 2.13
This indicates a CH₃ group with no adjacent hydrogen atoms.
It is shifted 0.8 ppm downfield to δ 2.13 by the adjacent C=O group.
4. Identification
The identified pieces are CH₃CH₂-, -(CO)-, and -CH₃. There is only one way to put them together: CH₃CH₂-(C=O)-CH₃.
The compound is butan-2-one.