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wariber [46]
3 years ago
7

The feed to a batch process contains equimolar quantities of nitrogen and methane. write an expression for the kilograms of nitr

ogen in terms of the total moles n(mol) of this mixture.
Chemistry
1 answer:
timama [110]3 years ago
3 0
1) number of moles of N2 = n/2

2) Number of moles of CH4 = n/2

3) Total number of moles of the mixture = n/2 + n/2 = n

4) Kg of N2

mass in grams = number of moles * molar mass

molar mass of N2 = 2 * 14.0 g/mol = 28 g/mol

=> mass of N2 in grams = (n/2) * 28 = 14n

mass of N2 in Kg = mass of N2 in grams * [1 kg / 1000g] = 14n/1000 kg = 0.014n kg

Answer: mass of N2 in kg = 0.014n kg
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How many grams of H, are needed to react with 2.75 g of N,?
Elena-2011 [213]

Answer:

0.6 grams of hydrogen are needed to react with 2.75 g of nitrogen.

Explanation:

When hydrogen and nitrogen react they form ammonia.

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N₂ + 3H₂ → 2NH₃

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Number of moles = 2.75 g / 28 g/mol

Number of moles = 0.098 mol

Now we will compare the moles of nitrogen with hydrogen from balance chemical equation:

                   N₂             :          H₂

                    1               :           3

                   0.098       :        3×0.098 = 0.3 mol

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