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wariber [46]
3 years ago
7

The feed to a batch process contains equimolar quantities of nitrogen and methane. write an expression for the kilograms of nitr

ogen in terms of the total moles n(mol) of this mixture.
Chemistry
1 answer:
timama [110]3 years ago
3 0
1) number of moles of N2 = n/2

2) Number of moles of CH4 = n/2

3) Total number of moles of the mixture = n/2 + n/2 = n

4) Kg of N2

mass in grams = number of moles * molar mass

molar mass of N2 = 2 * 14.0 g/mol = 28 g/mol

=> mass of N2 in grams = (n/2) * 28 = 14n

mass of N2 in Kg = mass of N2 in grams * [1 kg / 1000g] = 14n/1000 kg = 0.014n kg

Answer: mass of N2 in kg = 0.014n kg
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C.

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How might the molecules inside an ice pack be different from the liquid inside of an insulated cup?​
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The molecules inside the ice pack are frozen therefore they are stuck in place. The molecules inside an insulated cup aren't frozen but still stuck inside of their container so that they can not fly out.

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10. Which of state of matter has no definite shape but does have a definite volume?
il63 [147K]

Answer:

Gas, has no shape but does take up volume

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How many equivalents are in a solution that contains 0.25 moles Mg2+ and 0.50 moles Cl–?
Vinil7 [7]

Answer:

Explanation:

Mg²⁺ is divalent , hence

Molecular weight / 2 = equivalent weight .

.25 moles = 2 x .25 equivalents = .5 equivalents .

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7 0
3 years ago
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0144 0.0144 M solution. The pH of the resulting solution i
alexdok [17]

Answer:

The value of dissociation constant of the monoprotic acid is 1.099\times 10^{-3}.

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The pH of the solution = 2.46

pH=-\log[H^+]

2.46=-\log[H^+]

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HA\rightleftharpoons H^++A^-

Initially

0.0144         0      0

At equilibrium

(0.0144-x)       x       x

The expression if an dissociation constant is given by :

K_a=\frac{[A^-][H^+]}{[HA]}

K_a=\frac{x\times x}{(0.0144-x)}

x=[H^+]=0.003467 M

K_a=\frac{0.003467 \times 0.003467 }{(0.0144-0.003467 )}

K_a=1.099\times 10^{-3}

The value of dissociation constant of the monoprotic acid is 1.099\times 10^{-3}.

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