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2 years ago

How many types airI need a formula of calculating the s i unti of force

Physics

2 answers:

yKpoI14uk [10]2 years ago

4 0

The si unit of force is newton.

so, F is eqal to m*g

Dmitriy789 [7]2 years ago

4 0

Answer:

F=ma

Explanation:

force is actually a derived quantity

newton is a unit derived from kg.m/s^2

This is from Newton's second law of motion

F=ma

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A thin rod of length L and total charge Q has the nonuniform linear charge distribution λ(x)=λ0x/L, where x is measured from the

marissa [1.9K]

Answer:

Explanation:

λ(x) = λo x/ L

(a) The total charge is Q.

$Q=\int_{0}^{L}dq$

$Q=\int_{0}^{L}\frac{\lambda _{0}x}{L}dx$

$Q=\frac{\lambda _{0}}{2L}\left ( x^{2} \right )_{0}^{L}$

$Q=\frac{\lambda _{0}}{2L}$

λo = 2Q/L

(b)

Let at a distance x from the origin the charge is dq.

so, dq = (2Q/L) x/ L dx

$dq=\frac{2Qx}{L^{2}}dx$

The potential due to this small charge at a distance d to the left of origin

$dV = \frac{KdQ}{d+x}$

$\int_{0}^{V}dV = \frac{2KQ}{L^{2}}\int_{0}^{L}\frac{xdx}{d+x}$

$V = \frac{2KQ}{L^{2}}\int_{0}^{L}\left ( 1- \frac{d}{d+x}\right )dx$

$V = \frac{2KQ}{L^{2}}\times \left ( x-dln(d+x) \right )\int_{0}^{L}$

$V = \frac{2KQ}{L^{2}}\times \left ( L-dln(d+L)-0+dlnd \right )$

$V = \frac{Q}{4\pi \epsilon _{0}L^{2}}\times \left ( L+d\times ln\left (\frac{d}{d+L} \right )\right )$

4 0

3 years ago

Anne rode 3000 m east. She then turned and rode 2000 m to the west in 1000 seconds. What was her velocity?

yarga [219]

Answer:

1m/s [E]

Explanation:

So for displacement, its saying she went 3000m east and 2000m west. Since these two are in different directions, you would change the sign of one of them to change the direction;

3000m [E] + 2000m [W] = d

3000m [E] - 2000m [E] = d

1000m [E] = d

And its saying the time is 1000 seconds, so using velocity formula:

v = d/t

v=1000m[E] / 1000s

v = 1 m/s [E]

4 0

3 years ago

A vector is 9.55 m long and

Alexus [3.1K]

Answer:

Check pdf file

Explanation:

Download pdf

6 0

3 years ago

In the pair of supply and demand equations below, where x represents the quantity demanded in units of a thousand and p the unit

motikmotik

Answer:

Equilibrium quantity = 5

Equilibrium price = 40

Explanation:

given:

p = -x²-3x+80

p = 7x+5

For the equilibrium quantity the price from both the functions will be equal

thus, we have

-x² - 3x + 80 = 7x+5

⇒ x² +3x + 7x + 5 - 80 = 0

⇒x² + 10x - 75 = 0

now solving for x

x²- 5x + 15x -75 = 0

x(x-5) + 15(x-5) = 0

therefore, the two roots of the equation are

x = 5 and x = -15

since the quantity cannot be in negative

therefore, the equilibrium quantity will be = 5

now the equilibrium price can be found out by substituting the equilibrium quantity in any of the equation

thus,

p = -(5)² -3(5) + 80 = 40

p = 7(5) + 5 = 40

3 0

3 years ago

4. With respect to a mass of 1kg. (a) How much change in elevation must it undergo to change its potential energy by 1 kJ? (g=9.

mojhsa [17]

Answer:

102 m upwards.

Explanation:

Just from a qualitative analysis we can tell the mass it needs to go upwards. How much we determine with the fact that the increase will be - in absolute value - equal to the work gravity does on it to go down that same distance.

Fixed that work being 1 kJ, we get

$\vec F \cdot \vec{ \Delta h} = |F| |\Delta h| cos 0 = ( 9.8 N )\Delta h \cdot 1 = 10^3 J\\\Delta h = \frac {10^3}{9,8} m \approx 102 m$

4 0

1 year ago

How many types airI need a formula of calculating the s i unti of force​

How many types airI need a formula of calculating the s i unti of force