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svlad2 [7]
3 years ago
12

Which of the following statements are true? (mark all that apply)

Physics
1 answer:
kvv77 [185]3 years ago
8 0

Answer:

(a) and (b)

Explanation:

Energy is the capacity to do work, and exists in various forms. These forms can be converted one to another by the use of appropriate means. Some examples are sound, mechanical, solar, light, which causes the sensation of vision, etc. energy is measured in Joules (J).

The rate of transfer of energy is called power.

i.e Power = \frac{energy}{time}

It is measured in Watts (W).

When a white light is disperses into its colors, gray and black are not part of the colors. And a black sometimes could be as a result of the absorption of all other colors of light.

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An electron is moving the east with a speed of 5.0 × 106 m/s. There is an electric field of
Tanzania [10]

The velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

<h3>What is Electric field?</h3>

Electric field is the physical field that surrounds a charge.

<h3>How to find final velocity of the electron when it moves some distance in a certain electric field?</h3>
  • From Newton's second law, the acceleration the electron will be

a=F/m=qE/m

  • where q= charge of electron

E= electric field

m= mass of electron

=(−1.60×10^−19C)(3×10³N/C)/(9.11×10^-31kg)

=10¹⁵×0.526m/s²

  • The kinematics equation v²=v0²+2a(Δx)
  • where v=final velocity of the electron

v0=initial velocity of the electron =5×10⁶m/s

a=acceleration of the electron =10¹⁵×0.526m/s²

Δx=distance moved by the electron in east direction =1cm=10^-2m

  • Now v^2=(5×10⁶)²+2×10¹⁵×0.526×10^-2

=25×10¹²+10.52×10¹²

=35.52×10¹²

  • Now velocity of electron=5.95×10⁶m/s.

Thus , we can conclude that the velocity of the electron after moving a distance of 1cm in the electric field is 5.95×10⁶m.

Learn more about electric field here:

brainly.com/question/26199225

#SPJ1

5 0
2 years ago
PLZ hurry! Thank you
Alenkinab [10]

Answer:do it again

Explanation:

It will work

3 0
2 years ago
Which image represents the force on a positively charged particle caused by an approaching magnet?
Amanda [17]

Answer:

Image B represents the force on a positively charged particle caused by an approaching magnet.

Explanation:

The most fundamental law of magnetism is that like shafts repulse each other and dissimilar to posts pull in one another; this can without much of a stretch be seen by endeavoring to put like posts of two magnets together. Further attractive impacts additionally exist. On the off chance that a bar magnet is cut into two pieces, the pieces become singular magnets with inverse shafts. Also, pounding, warming or winding of the magnets can demagnetize them, on the grounds that such dealing with separates the direct game plan of the particles. A last law of magnetism alludes to maintenance; a long bar magnet will hold its magnetism longer than a short bar magnet. The domain theory of magnetism expresses that every single enormous magnet involve littler attractive districts, or domains. The attractive character of domains originates from the nearness of significantly littler units, called dipoles. Iotas are masterminded in such a manner in many materials that the attractive direction of one electron counteracts the direction of another; in any case, ferromagnetic substances, for example, iron are unique. The nuclear cosmetics of these substances is with the end goal that littler gatherings of particles unite as one into zones called domains; in these, all the electrons have the equivalent attractive direction.

4 0
2 years ago
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 38 m in front of you. Your reaction tim
Bingel [31]

Answer:

given,

speed of the car = 20 m/s

final speed of car = 0 m/s

distance between car and the deer = 38 m

reaction time, t = 0.5 s

deceleration of the car = 10 m/s².

a) distance between deer and car

  distance travel in the reaction time

   d₁ = v x t

   d₁ = 20 x 0.5 = 10 m

   distance travel after you apply brake

   using equation of motion

   v² = u² + 2 a s

   0 = 20² - 2 x 10 x s

    s =  20 m

total distance traveled by the car

D = d₁ + d₂

D = 20 + 10 = 30 m

  distance between car and the deer = 38 m - 30 m

                                                              = 8 m

b) now, maximum speed car.

   distance travel in reaction time

    d₁ = s x t

    d₁ = 0.5 V

distance left between them

   d₂ = 38 - d₁

   d₂ = 38 - 0.5 V

   distance travel after you apply brake

   using equation of motion

    v² = u² + 2 a d₂

    0 = (V)² - 2 x 10 x (38 - 0.5 V)

     V² + 10 V - 760 = 0

now, solving the quadratic equation

  x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

  V = \dfrac{-10\pm \sqrt{10^2-4(1)(-760)}}{2(1)}

         V = 23.01 , -33.01

rejecting the negative term.

hence, maximum speed of the car could be V = 23.01 m/s

 

7 0
3 years ago
Which three statements about electromagnetic radiation are true?
grandymaker [24]
I think that numbers one, three, and four are true
3 0
3 years ago
Read 2 more answers
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