First the nth term which is 6n-3
So 6x45-3 is your answer
Answer:
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If one person is randomly selected what is the probability that the persons IQ is between 110 and 130
This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.
X = 130



has a pvalue of 0.9772
X = 110



has a pvalue of 0.7486
0.9772 - 0.7486 = 0.2286
22.86% probability that the persons IQ is between 110 and 130
Answer:
<u>One Rectangular Pan</u>
Step-by-step explanation:
Part C cannot be answered since the dimensions of the pool are not given. Please check the question.
The cake pans may be compared by calculating the volume of each shape:
Rectangular pan: Volume = Length x Width x Height
Volume Rectangle = (13")*(9")*(2") = <u>234 in^3</u>
Round pan: Volume = 
Volume Round = (3.14)*(4")^2(2") = 100.5 in^3
Two round pans will hold 2*(100.5 in^3) or 201 in^3 of batter
One rectangular pan holds 234 in^3.
Go with the rectangular pan if you want more cake.
Answer:
16 I guess
Step-by-step explanation:
2*2 is 4
Then 4 times 4 is 16.
Answer:
Step-by-step explanation:
In order to convert 0.0004578, which is in decimal, to scientific notation, all we need to do in this case is to move our decimal point to the right till we arrive at the first number that is not a zero, and then eliminate all the zero.
In this case, we will have to move the decimal point 4 spaces to our right, which would mean our exponent would be negative. The number of decimal spaces we moved to our right would be the value of our exponent, which is -4 in this case.
Thus, we have:
