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bekas [8.4K]
3 years ago
10

I'll be sure to mark a brainliest!! :))

Mathematics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

<h2>5√3 cm</h2>

solution,

hypotenuse (h)=10 cm

base(b)=5 cm

perpendicular (p)=?

Now,

Using Pythagoras theorem,

{h}^{2}  =  {p}^{2}  +  {b}^{2}  \\  {p }^{2}  =  {h}^{2}  -  {b}^{2}  \\ or \:  {p}^{2}  =  {(10)}^{2}  -  {(5)}^{2}  \\ or \:  {p}^{2}  = 100 - 25 \\ or \:  {p}^{2}  = 75 \\ or \: p =  \sqrt{75}  \\ p = 5 \sqrt{3}  \: cm

Hope this helps...

Good luck on your assignment...

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The temperature outside changed from 76°F to 46°F over a period of five days. If the temperature changed by the same amount each
JulijaS [17]

。☆✼★ ━━━━━━━━━━━━━━━  ☾

Work out the total change:

76 - 46 = 30

Divide this by the number of days:

30/5 = 6

As the temperature decreased, it would have a minus value in front of it

Thus, the answer is option B

Have A Nice Day ❤

Stay Brainly! ヅ

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8 0
3 years ago
A 20 foot ladder is leaning up against the side of a house the distance between the house and the base of the ladder is 4 feet f
Pie

Answer:

78.5°

Step-by-step explanation:

We solve for the above question, using the formula for the Trigonometric function of Cosine

cos θ = Adjacent/Hypotenuse

Adjacent = The distance between the house and the base of the ladder = 4 feet

Hypotenuse = Length of the Ladder = 20 feet

Hence,

cos θ = 4/20

θ = arc cos(4/20)

θ = 78.463040967°

Approximately = 78.5°

Therefore, the angle that the ladder makes with the ground is 78.5°

6 0
3 years ago
A recipe calls for 2/3 cup of chopped walnuts. You chop 4 walnuts and get 1/4 of the amount you need. How much more of a cup of
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liraira [26]

The answer is: B. Even function.

The explanation for this exercise is shown below:

1. You must substitute x with -x in the function:

f(x)=x^{2} +3\\ f(-x)=(-x)^{2} +3\\ f(-x)=x^{2} +3

2. As you can see, f(-x)=f(x), therefore it is an Even function.

8 0
4 years ago
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Answer:

Closer to 30.

Step-by-step explanation:

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Hope this helps!

If not, I am sorry.

4 0
3 years ago
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