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elixir [45]
3 years ago
11

Use properties to find the sum or product 21+25+39+5

Mathematics
2 answers:
pashok25 [27]3 years ago
4 0
The sum of this equation is 90
V125BC [204]3 years ago
4 0

the sum or product of  21+25+39+5 is 90

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Rafael received 5/6 of 180 volts how many votes did he receive
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Here is an example:

If you divided 64 by 5/8, then you would get a number larger than 64.

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3 years ago
Which one would be a result in a repeating decimal 5/11 1/9 3/4 3/7
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3 years ago
Calculus A hard problem help please
dexar [7]
∑x = 1 + 2 + 3 + 4 + 5 + 6 = 21
∑y = 8 + 3 + 0 + 1 + 2 + 1 = 15
∑x^2 = 1 + 4 + 9 + 16 + 25 + 36 = 91
∑y^2 = 64 + 9 + 0 + 1 + 4 + 1 = 79
∑xy = 8 + 6 + 0 + 4 + 10 + 6 = 34

r = (n∑xy - ∑x∑y)/(sqrt(n∑x^2 - (∑x)^2)*sqrt(n∑y^2 - (∑y)^2)) = (6(34) - 21(15))/(sqrt(6(91) - (21)^2)*sqrt(6(79) - (15)^2)) = (204 - 315)/(sqrt(546 - 441)*sqrt(474 - 225)) = -111/(sqrt(105)*sqrt(249)) = -111/(10.25*15.78) = -111/161.7 = -0.68

3 0
3 years ago
Read 2 more answers
Solve for y
Andreas93 [3]

Answer:

y = 3

Step-by-step explanation:

2y - 3 = \sqrt{3y^2-10y+12}

square both sides to remove sqrt bracket

(2y - 3)^2 = ( \sqrt{3y^2-10y+12} )^2

simplify both sides

(2y - 3)(2y - 3) = 3y^2 - 10y + 12

4y^2 - 12y + 9 = 3y^2 - 10y + 12

bring all value to left side

y^2 - 2y - 3 = 0

factor

(y - 3)(y + 1)

solve for y

y = 3, y = -1

When plugged back into the equation, only y = 3 is true

8 0
3 years ago
Read 2 more answers
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