2x^3 - 2x - 4
3x + 1 6x^4 + 2x^3 - 6x^2 - 14x - 1
6x^4 + 2x^3
-6x^2 - 14x - 1
-6x^2 - 2x
-12x - 1
-12x - 4
3
3x + 1 is not a factor of the dividend because, dividing the dividend with 3x + 1 gives a remainder.
X6 – 9x3 + 8 = 0
let u = x^3
u^2 - 9u + 8 = 0
(u-8)(u-1) = 0
u = 1,8
back substitute
1 = x^3
8 = x^3
<span>x = 1 , 2</span>
4 dollars they contributed 4 dollars each
Answer:
5- ASA
6- SSS
7- SAS
8- SSS
Step-by-step explanation:
Answer:
it's 67
Step-by-step explanation:
