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Virty [35]
2 years ago
15

I need help with math!!! time is running out!!! will mark brainliest!!!

Mathematics
2 answers:
Alexus [3.1K]2 years ago
5 0
1.

Answer B.

2.

Answer B.

3.

Answer B.

4.

Answer B.

5.

Answer B.
umka2103 [35]2 years ago
3 0
1.C

2.A

3.C

4.D

5.B

I hope I helped!
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Which equation is a step in solving the equation 5 - 3x + 2 = 19?
Leni [432]

Answer:

D. 5-3x = 17

Step-by-step explanation:

The step carried out was subtracting 2 from both sides.

5 - 3x + 2 = 19 \\ 5 - 3x + 2 - 2 = 19 - 2 \\ 5 - 3x = 17

4 0
3 years ago
Pls help 15 points pls hurry
Alexus [3.1K]

Answer:

5k and -3k are like variables

constants 7 and -2 are like terms

5+2k+n is equivalent expression

Step-by-step explanation:

3 0
2 years ago
A machine cuts 25 circuit boards every 5 minutes. What is the unit rate of production for the machine?
Sladkaya [172]

Answer:

  • B- 5/1 boards/minutes

Step-by-step explanation:

<u>Unit rate is the number of circuit boards a minute:</u>

  • 25 boards every 5 minutes >>
  • 25/5 boards every 5/5 minutes >>
  • 5/1 boards/minutes

Correct choice is B

3 0
2 years ago
At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4
wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

1.

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}

2.

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\  \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}

3.

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\  \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\  \\ \therefore E_1\equiv E_2=55580ft \end{gathered}

6 0
8 months ago
You can afford a $1350 per month mortgage payment. You’ve found a 30 year loan at 7% interest.
Mice21 [21]
A) 45 because 1350 divide by 30 equals 45. So 45 dollars u can afford

B) 1350 because 45 x 30 = 1350


C) 7% because it’s 7% to begin with
4 0
3 years ago
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