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2 years ago

13

(-11x^2 +6) - (14x^2 +2)

1 answer:

Nataly [62]2 years ago

8 0

Answer:

−1(5−2)(5+2)

Step-by-step explanation:

Eliminate redundant parentheses

(−11²+6)−1(14² +2)

Distribute

−11² + 6 -- 1(14² +2)

−11² + 6 - 14² − 2

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3 years ago

Help on college algebra, question is on the picture!

kodGreya [7K]

$\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x}$ is given
here , $\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x}$
or, $\frac{7x^{2} +x +2x-4 }{x(x-2)} = \frac{-4}{ x^{2} -2x}$
or, $\frac{7 x^{2} +3x-4}{ x^{2} -2x} = \frac{-4}{ x^{2} -2x}$
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8 0

3 years ago

Mary took a math test and she got four questions incorrect and 21 correct. What percent did answer correctly?

AnnZ [28]

Answer:

84%

Step-by-step explanation:

21 correct + 4 wrong = 25 questions in total

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6 0

3 years ago

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Annette [7]

Answer:

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Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Through: (-3,0), perp. to y = 3x - 1

Marrrta [24]

Answer:

$y=-\dfrac{1}{3}x-1$

Step-by-step explanation:

<u>Given: </u>

line y=3x-1

point (-3,0)

<u>Write:</u> equation of the line that is perpendicular to the given and passes through the point (-3,0)

<u>Solution:</u>

The slope of the given line is $m=3$

If $m_1$ is the slope of perpendicular line, then

$m\cdot m_1=-1\\ \\3m_1=-1\\ \\m_1=-\dfrac{1}{3}$

So, the equation of the needed line is $y=-\dfrac{1}{3}x+b.$

Find b. This line passes through the point (-3,0), so its coordinates satisfy the equation:

$0=-\dfrac{1}{3}\cdot (-3)+b\\ \\0=1+b\\ \\b=-1\\ \\y=-\dfrac{1}{3}x-1$

7 0

3 years ago