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Alex17521 [72]
3 years ago
13

Which of the following p values will lead us to reject the null hypothesis if the level of significance equals .05?

Mathematics
1 answer:
V125BC [204]3 years ago
7 0

Answer:

So then our significance level is \alpha=0.05 and we need to remember these two conditions:

1) If the p value p_v we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value p_v \geq \alpha we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

Step-by-step explanation:

We want to know for which value we would REJECT the null hypothesis.

So then our significance level is \alpha=0.05 and we need to remember these two conditions:

1) If the p value p_v we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value p_v \geq \alpha we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

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What is the value of x (x+2)(x-3)=0
wolverine [178]

Answer:

x = 3 or x = -2

Step-by-step explanation:

Solve for x over the real numbers:

(x + 2) (x - 3) = 0

Hint: | Find the roots of each term in the product separately.

Split into two equations:

x - 3 = 0 or x + 2 = 0

Hint: | Look at the first equation: Solve for x.

Add 3 to both sides:

x = 3 or x + 2 = 0

Hint: | Look at the second equation: Solve for x.

Subtract 2 from both sides:

Answer: x = 3 or x = -2

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$3.18

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djyliett [7]

Answer:

y =   {e}^{3}

Step-by-step explanation:

f(x) =  {e}^{3x}  \\  \\ plug \: x = 1 \\  \\ f(1) =  {e}^{3 \times 1}  \\  \\ f(1) =  {e}^{3}   \\  \\ plug \: f(1) = y \\  \\ y =   {e}^{3}

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If f(x-3)=x^2-4x+5, what's f(1-x)​
olganol [36]

Answer:

\large\boxed{f(1-x)=x^2-4x+5}

Step-by-step explanation:

f(x-3)=x^2-4x+5\\\\f((x-3)+3)\to\text{put x + 3 to the equation of the function:}\\\\f(x-3+3)=(x+3)^2-4(x+3)+5\\\text{use the distributive property and}\ (a+b)^2=a^2+2ab+b^2\\f(x)=x^2+2(x)(3)+3^2+(-4)(x)+(-4)(3)+5\\f(x)=x^2+6x+9-4x-12+5\qquad\text{combine like terms}\\f(x)=x^2+(6x-4x)+(9-12+5)\\f(x)=x^2+2x+2\\\\f(1-x)\to\text{put 1 - x to the equation of the funtion f(x):}\\\\f(1-x)=(1-x)^2+2(1-x)+2\\\text{use the distributive property and}\ (a-b)^2=a^2-2ab+b^2

f(1-x)=1^2-2(1)(x)+x^2+(2)(1)+(2)(-x)+2\\f(1-x)=1-2x+x^2+2-2x+2\qquad\text{combine like terms}\\f(1-x)=x^2+(-2x-2x)+(1+2+2)\\f(1-x)=x^2-4x+5

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3 years ago
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