Steel is an example of an interstitial alloy, because the very small carbon atoms fit into interstices of the iron matrix.
Let's solve ~
Initial concentration of weak acid HA = 0.200 M
and dissociation constant (
) is :
Now, at initial stage :
At equilibrium :
Now, we know :
![\qquad \sf \dashrightarrow \: { K_a = \dfrac{[H+] [A-]}{[HA]}}](https://tex.z-dn.net/?f=%5Cqquad%20%5Csf%20%20%5Cdashrightarrow%20%5C%3A%20%7B%20K_a%20%3D%20%5Cdfrac%7B%5BH%2B%5D%20%5BA-%5D%7D%7B%5BHA%5D%7D%7D%20)
( big brackets represents concentration )
As you go across a period, radius shrinks because you are adding protons. The added positive charge increases pull on the electron shells.
As you go down a group, radius gets larger because you are increasing shells of electrons. This increases shielding of the nucleus' positive charge, so the electrons are not pulled in as much.
To find the empirical formula you would first need to find the moles of each element:
58.8g/ 12.0g = 4.9 mol C
9.9g/ 1.0g = 9.9 mol H
31.4g/ 16.0g = 1.96 O
Then you divide by the smallest number of moles of each:
4.9/1.96 = 2.5
9.9/1.96 = 6
1.96/1.96 = 1
Since there is 2.5, you find the least number that makes each moles a whole number which is 2.
So the empirical formula is C5H12O2.
The coefficient for aluminium is 4.
Explanation:
We have the following chemical reaction:
Al + O₂ → Al₂O₃
In order to balance the chemical equation the number of the atoms entering the reaction should be equal to the number of atoms leaving the reaction.
2 Al + 3/2 O₂ → Al₂O₃
However we need integer numbers so we multiply everything with 2.
4 Al + 3 O₂ → 2 Al₂O₃
The coefficient for aluminium is 4.
Learn more:
about balancing chemical equations
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