A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.
<h3>What is a decomposition reaction?</h3>
A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.
- Step 1: Write the balanced equation for the decomposition of KHCO₃.
2 KHCO₃(s) → K₂CO₃(s) + CO₂(g) + H₂O(l)
The mass loss of 0.275 g is due to the gaseous CO₂ that escapes the sample.
- Step 2: Calculate the mass of KHCO₃ that formed 0.275 g of CO₂.
In the balanced equation, the mass ratio of KHCO₃ to CO₂ is 200.24:44.01.
0.275 g CO₂ × 200.24 g KHCO₃/44.01 g CO₂ = 1.25 g KHCO₃
- Step 3: Calculate the mass percentage of KHCO₃ in the sample.
There are 1.25 g of KHCO₃ in the 1.775 g sample.
%KHCO₃ = 1.25 g/1.775 g × 100% = 70.4%
A 1.775g sample mixture of KHCO₃ is decomposed by heating. if the mass loss is 0.275g, the mass percentage of KHCO₃ is 70.4%.
Learn more about decomposition reactions here: brainly.com/question/14219426
Answer:
1) 18.91 mL
2) 2.35 %
Explanation:
1. The volume of base that was required is equal to the <em>difference between the reading at the end of the titration and the reading at the beginning</em>:
- V = 20.95 mL - 2.04 mL = 18.91 mL
2. The mass percent can be written as:
- Mass Percent = Mass solute / Total mass * 100%
For this problem:
We<u> input the data and calculate the mass percent</u>:
- % mass = 2.28/96.92 * 100% = 2.35 %
Answer:
The answer is option C.
Explanation:
A covalent bonded molecule when not dissolved in an aqueous solution does not contain any ions hence does not conduct electricity making it an insulator.
Hope this helps you.
Propanal will form silver mirror upon heating with Tollen's reagent while propanoic acid will not respond.
