3 years ago

Hydrochloric acid + aluminum hydroxide ®

Chemistry

1 answer:

makkiz [27]3 years ago

3 0

The answer is C. and D. water and aluminum

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Calculate the volume of H2(g) at 273 K and 2.00 atm that will be formed when 275 mL of 0.725 M HCl solution reacts with excess M

Ksenya-84 [330]

Answer:

$V=1.11L$

Explanation:

Hello,

In this case, the chemical reaction is:

$2HCl+Mg\rightarrow MgCl_2+H_2$

Thus, the reacting moles of hydrochloric acid are computed with the volume of the given solution:

$n_{HCl}=0.725\frac{mol}{L} *0.275L=0.199molHCl$

Hence, we perform the proportional factors having the 2:1 molar relationship between hydrochloric acid and hydrogen to find the yielded moles of hydrogen:

$n_{H_2}=0.199molHCl*\frac{1molH_2}{2molHCl} =0.0995molH_2$