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weeeeeb [17]
3 years ago
12

Coal can be converted to methane gas by a process called coal gasification. The equation for the reaction is the following: 2 C

(s) 2 H2O (l) --> CH4 (g) CO2 (g) What mass in grams of carbon is required to react with water to form 1.00 mol CH4
Chemistry
1 answer:
zloy xaker [14]3 years ago
3 0

Answer:

24 g of C are needed to produce 1mol of CH₄

Explanation:

The reaction is:

2C (s) +  2H2O (l) → CH4(g) + CO2 (g)

2 moles of carbon react with 2 moles of water in order to produce 1 mol of methane and 1 mol of carbon dioxide.

If we want to produce 1 mol of methane, we need 2 moles of C

Let's find out the mass → 2 mol . 12 g/1 mol = 24g

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a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the
butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}

Given ,  

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7  ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (21.7 + 273.15) K = 294.85 K  

T₂ = (28.1 + 273.15) K = 301.25 K  

Using above equation as:

\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}

\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K  }}{0.998\ atm}

n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol

Solving for n₂ , we get:

n₂ = 0.39 mol

7 0
3 years ago
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Answer:

Explanation:

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There's light energy given off.

There's heat energy given up.

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