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Scilla [17]
3 years ago
14

Does anyone understand the Circuit Analysis paper. I'm completely lost. If anyone can help, PLEASE DO!!!

Physics
1 answer:
MrMuchimi3 years ago
4 0

It's possible that I might have a good chance of understanding it,
and possibly even explaining it, if I could <em><u>SEE</u></em> it !


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How do these frogs vary from each other ? Give a reason to support your answer.
PolarNik [594]

Answer:

frogs have lungs to breath on land  and gills to  breath underwater that makes a frog different from each other

3 0
3 years ago
If a Ferrari, with an initial velocity of 14m/s, accelerates at a rate of 60
ss7ja [257]

Answer:

254

Explanation:

use the formula "final Velocity- initial velocity / time = acceleration"

so "X - 14 /4 = 60"

60 x 4 = X - 14

240 +14 = X

X = 254

8 0
3 years ago
Read 2 more answers
What does the sun do
Fofino [41]

Answer:

All of the above. If you had to pick one it would be D.

Explanation:

The sun gives off many kinds of radiation other than light and heat it also Emits radio waves ultraviolet rays and x-rays

8 0
3 years ago
A 3.0 kg cart moving due east at 4.0 m/s collides with a 6.0 kg cart moving due west. the carts stick together and come to rest
denpristay [2]
The problem about describes a perfectly inelastic collision. We are tasked to find the initial velocity of an object having a mass of 6 kg moving due west. It is given in the problem that after collision the cart sticks together and it stops. Thus, the final mass is the sum of the two cart and the final velocity is zero. For a perfectly inelastic collision,

m1v1-m2v2=vf(m1+m2)
By Substitution,

3(4)-6(v2)=0
6v2=12
v2=2

Therefor, the initial velocity if a 6 kg cart is 2 m/s
3 0
4 years ago
The question is in the attachment!!​
Bingel [31]

Explanation:

|F|= B/2

B/2 = √(A²+B²+2ABcosθ) ------(1)

Since the resultant of A and B is perpendicular to Vector A

tan90°= BSinθ/(A+BCosθ)

(A+BCosθ)=0

Cosθ=-A/B ----(2)

Using equation (1)

B/2 = √(A²+B²+2ABcosθ)

B/2 = √(A²+B²+2AB×-A/B)

B/2=√(A²+B²-2A²)

B/2=√(B²-A²)

B²/4=B²-A²

A²=B²-B²/4

A²=3B²/4

A=√3B/2

Using equation (2)

Cosθ=-A/B

Cosθ=-[√3B/2]/B

Cosθ=-√3/2

θ= cos^-1 (-√3/2)

θ= 150°

7 0
3 years ago
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