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3 years ago

The actual speed of the car at the top of the hill is 20.0m/s. What is the reason for this difference in velocity?

Physics

1 answer:

olga2289 [7]3 years ago

6 0

Answer:

Please find the answer in the explanation.

Explanation:

Given that the actual speed of the car at the top of the hill is 20.0m/s. What is the reason for this difference in velocity?

Speed is a scalar quantity that is, it has only magnitude but no direction.

While velocity is a vector quantity, that is, it has both magnitude and direction.

If the actual speed of a car is 20 m/s, that is the magnitude of the speed only without direction.

The velocity will therefore be of the same magnitude but with addition of direction. Either west, east or north south.

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A 14 kg block lifted 5 m has a gravitational potential energy of

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Answer:

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Explanation:

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P.E = 14 × 5 × 10
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A banked circular highway curve is designed for traffic moving at 58 km/h. The radius of the curve is 201 m. Traffic is moving a

skelet666 [1.2K]

Answer:0.077

Explanation:

Given

banked designed for traffic moving at $58 km/h\approx 16.11 m/s$

Radius of the curve 201 m

Actual traffic velocity = $37 km/h approx 10.27 m/s$

For banking of road

$tan\theta =\frac{v^2}{rg}$

$tan\theta =\frac{16.11^2}{201\times 9.81}$

$\theta =7.49^{\circ}$

Centripetal acceleration is given by

$a=\frac{v^2}{r}$

Taking component of centripetal acceleration

along and perpendicular to surface

$a_{parallel}=\frac{v^2cos\theta }{r}$

$a_{perpendicular}=\frac{v^2sin\theta }{r}$

From FBD

$mgsin\theta -f_s=ma_{parallel}$

$f_s=mgsin\theta -ma_{parallel}$ ----1

where $f_s$ is frictional force

$N-mgcos\theta =ma_{perpedicular}$

$N=mgcos\theta +ma_{perpedicular}$ ----2

and we know coefficient of friction is given by

$\mu =\frac{f_s}{N}$

$\mu =\frac{mgsin\theta -ma_{parallel}}{mgcos\theta +ma_{perpedicular}}$

$\mu =\frac{gsin\theta -\frac{v^2cos\theta }{r}}{gcos\theta +\frac{v^2sin\theta }{r}}$

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3 years ago

A sound wave with a power of 8.8 × 10–4 W leaves a speaker and passes through section A, which has an area of 5.0 m2. What is th

statuscvo [17]

The intensity of the sound wave is defined as the ratio between the power of the wave and the area through which the wave passes:
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where
I is the intensity
P is the power
A is the area

If we use the data of the problem, $P=8.8 \cdot 10^{-4}W$ and $A=5.0 m^2$ , we find the intensity of the sound wave:
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3 years ago

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4 years ago