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2 years ago

What is the role of Langerhans cells?

1 answer:

4 0

Langerhans cells exist on the surface of the skin. They help to protect you by keeping dangerous microbes from entering your body. Langerhans cells do this in two very different ways: by protecting your skin from infection and also by stimulating allergic reactions.

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An object travels in a circular path of radius 5.0 meters at a uniform speed of 10. m/s. What is the magnitude of the object's a

vladimir1956 [14]

I think F= mv²/r
And F=ma
So, ma = mv²/r
a = v²/r
a = 100/5
a = 20 m/s

8 0

3 years ago

Read 2 more answers

Which mixture can be separated based on differences in particle size of the components? Check all that apply.

slamgirl [31]

It’s not Cereal and Milk, carbonated drinks, and smoky air

6 0

3 years ago

Hey!

pav-90 [236]

Answer:

Hydraulic pressure exerted on glass slab, ρ=10 atm

Bulk modulus of glass, B=37×10^9 Nm^−2

Bulk modulus, B=P/(ΔV/V)

where,

ΔV/V= Fractional change in volume

ΔV/V=P/B

=10×1.013×10^5 /(37×10 ^9)

=2.73×10^-5

Therefore, the fractional change in the volume of the glass slab is 2.73×10^-5

Hope it helps

3 0

2 years ago

Read 2 more answers

A cube has a drag coefficient of 0.8. What would be the terminal velocity of a sugar cube 1 cm on a side in air ( = 1.2 kg/mº)?

anzhelika [568]

0.495 m/s

Explanation

the formula for the terminal velocity is given by:

$\begin{gathered} v=\sqrt[]{\frac{2mg}{\sigma AC}} \\ \text{where} \\ \end{gathered}$

m is the mass

g is 9.81 m/s²

ρ is density

A is area

C is the drag coefficient

then

Step 1

Let's find the mass

$\begin{gathered} \sigma=\frac{m}{v} \\ m=\sigma\cdot v \\ \text{mass}=(2\cdot10^3\frac{\operatorname{kg}}{m^3})\cdot(0.01m)^3 \\ \text{mass}=(2\cdot10^3\frac{\operatorname{kg}}{m^3})\cdot(1\cdot10^{-6}) \\ \text{mass}=2\cdot10^{-3}\operatorname{kg} \\ \text{mass}=0.002\text{ kg } \\ \text{Area}=(0.01\text{ m}\cdot0.01m)=0.0001m^2 \end{gathered}$

now, replace

$\begin{gathered} v=\sqrt[]{\frac{2mg}{\sigma AC}} \\ v=\sqrt[]{\frac{2(0.002kg)(9.81\text{ }\frac{m}{s^2})}{(2\cdot10^3\frac{\operatorname{kg}}{m^3})(0.0001m^2)0.8}} \\ v=\sqrt[]{\frac{0.03924\frac{\operatorname{kg}m}{s^2}}{0.16\frac{\operatorname{kg}}{m^{}}}} \\ v=\sqrt[]{0.2452\frac{m^2}{s^2}} \\ v=0.495\text{ m/s} \end{gathered}$

hence, the answer is 0.495 m/s

3 0

9 months ago

A hi-lo lifts an 25 N skid to top of a pallet rack. The pallet rack is 3.6 meters tall. The hi-lo takes 12 seconds to get the sk

mojhsa [17]

Answer:

7.5Watts

Explanation:

Given parameters:

Force of lift = 25N

Height = 3.6m

Time = 12s

Unknown:

Power output = ?

Solution:

Power is the rate at which work is done ;

Power = $\frac{force x height }{time}$

Power = $\frac{25 x 3.6}{12}$ = 7.5Watts

8 0

2 years ago