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2 years ago

What is the role of Langerhans cells?

1 answer:

4 0

Langerhans cells exist on the surface of the skin. They help to protect you by keeping dangerous microbes from entering your body. Langerhans cells do this in two very different ways: by protecting your skin from infection and also by stimulating allergic reactions.

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Quark gluon plasma (qgp) is what kind of state of matter I.e. it’s equation of state is what?

sladkih [1.3K]

a 10 kg block reaches a point with a velocity of 15 m per second and slides down a rough track my the coefficient of the kinetic energy between the two surface ab and the block iis0.52

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1 year ago

What is direct result of having greenhouse gases in the atmosphere?

11111nata11111 [884]

Earths atmosphere heats up polars melt

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3 years ago

Use Percentages Given that the molecular mass of magnesium

ira [324]

Answer:

27%

Explanation:

15.999 divided by 58.32 = .27433128

Move the decimal place over 2 places.

27%

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3 years ago

You sit at the middle of a large turntable at an amusement park as it is set spinning on nearly frictionless bearings, and then

jolli1 [7]

Answer:

Decrease

Explanation:

If you crawl to the rim the rotational speed will decrease. The law of conservation of angular momentum supports this answer. And it states that :

"When the net external torque acting on a system about a given axis is. zero , the total angular momentum of the system about that axis remains constant."

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3 years ago

Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road oriented at an angle of 25

rjkz [21]

Answer:

8.6 miles

Explanation:

In order to calculate the straight-line distance between the starting point and the ending point, we need to resolve each part of the displacement into two perpendicular directions, let's say horizontal (x) and vertical (y) directions.

In the first part, Erica moves for 5.2 miles 25∘ north of east. Resolving into the two directions:

$d_{1x} = 5.2 cos 25^{\circ}=4.7 mi\\d_{1y} = 5.2 sin 25^{\circ} =2.2 mi$

In the second part, Erica moves 5.0 miles north, so the components are

$d_{2x} = 0\\d_{2y} = 5.0 mi$

So the components of the net displacement are

$d_x = d_{1x}+d_{2x}=4.7+0 = 4.7 mi\\d_y = d_{1y}+d_{2y} =2.2+5.0 = 7.2 mi$

And the magnitude of the net displacement is

$d=\sqrt{d_x^2 +d_y^2}=\sqrt{4.7^2+7.2^2}=8.6 mi$

8 0

3 years ago