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user100 [1]
3 years ago
12

Given that there are three spotted Pacific banana slugs for every four non spotted Pacific banana slug(s) in Arcata's community

forest, let xx represent the probability of drawing a single spotted Pacific banana slug from a single draw of both varieties of spotted and non spotted slugs.
Mathematics
1 answer:
vovangra [49]3 years ago
6 0

Answer:

The probability of selecting a single spotted Pacific banana slug will be \frac{3}{7}.

Step-by-step explanation:

There are three spotted Pacific banana slugs for every four non spotted Pacific banana slugs.

There are three  spotted Pacific banana slugs in every group of 7 Pacific banana slugs.

There are four non spotted Pacific banana slugs in every group of 7 Pacific banana slugs.

Therefore the probability of selecting a single spotted Pacific banana slug will be

\frac{number \hspace{0.1cm} of  \hspace{0.1cm}  spotted  \hspace{0.1cm}  Pacific  \hspace{0.1cm}  banana  \hspace{0.1cm}  slugs  \hspace{0.1cm}  in  \hspace{0.1cm}  group  \hspace{0.1cm}  of  \hspace{0.1cm}  7  \hspace{0.1cm} Pacific \hspace{0.1cm} banana \hspace{0.1cm} slugs}{number  \hspace{0.1cm}  of   \hspace{0.1cm}  slugs  \hspace{0.1cm}  in  \hspace{0.1cm}  a \hspace{0.1cm} group  \hspace{0.1cm}  of  \hspace{0.1cm}  7  \hspace{0.1cm}  Pacific  \hspace{0.1cm}  banana \hspace{0.1cm} slugs} = \frac{3}{7}.

The probability of selecting a single non spotted Pacific banana slug will be = \frac{4}{7}.

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