Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Answer:
65 cents
Step-by-step explanation:
divide 10 by 2.25 to get the factor. Next divide 2.9 by that to get your answer. 10/2.25 = 4 4/9. 2.9/ 4 4/9 = 0.6525 --> 0.65
By definition, an expression does not contain AN EQUALS SIGN (=).
Answer:
3-n=14
Step-by-step explanation less than a number!!! If a number is unkown it would be a variable, a letter,
Answer:
27.183m. squared
Step-by-step explanation:
Find the base, then find the volume
Base:
(2.6*4.1*0.5)=
(10.66*0.5)=
5.33
Volume:
(5.33*5.1)=
27.183
Hope that this helped!