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kati45 [8]
3 years ago
5

If 12$=1gram how many dollars equal an ounce

Mathematics
1 answer:
Marina CMI [18]3 years ago
8 0
There is 28 grams in an ounce, so 12 times 28 equals......?
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!!!!SHOW WHY IT IS CORRECT PLEASEEE!!!!<br>\and please don't steal the points :(
jek_recluse [69]

Answer: Its correct because 3(2t+d) = 6t + 3d are equal.

Step-by-step explanation:

First we need to solve the equation

3( 2t+d ) = 6t + 3d              //// Do some distributive property

6t + 3d = 6t + 3d               //// Do you see it . . . They are equal to each other.

So its true.

4 0
3 years ago
Read 2 more answers
Round three significant figures 12.3456
kow [346]

Answer:

12.3

Step-by-step explanation:

Round it where you have 3 numbers that are not 0.

12.3456

round to the hundredths place

12.34 (round to 4)

12.3 (3 sigfigs)

7 0
3 years ago
Read 2 more answers
Identify the polygon and classify it as regular or irregular.
Nimfa-mama [501]

Answer: YES

Step-by-step explanation: A polygon which has all its sides of equal length and all its angles of equal measures is called a regular polygon. ... Therefore, a regular pentagon is a regular polygon. Irregular polygon: A polygon which has all its sides of unequal length and all its angles of unequal measures is called an irregular polygon.

3 0
3 years ago
Read 2 more answers
What is the volume of a sphere with a diameter of 4 meters? (Use 3.14 for π.)
mixer [17]

Answer:

volume of the sphere =33.493m^3

Step-by-step explanation:

Given:

Diameter= 4 m,   Radius = 4/2 =2 m

Volume of a sphere=  \frac{4}{3} *\pi* r^3

= \frac{4}{3} *\pi* 2*2*2                                                :\pi =3.14

=  \frac{4}{3} *3.14*2*2*2

=  1.33*3.14*2*2*2

=33.493m^3

The volume of the sphere with the radius of 2 m is 33.493m^3

6 0
3 years ago
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
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