Question

Find the volume of the composite solid. Round your answer to the nearest tenth.

Answer 1

The answer is 1474ft

Answer 2

Answer:

The volume of the composite solid is $1206.4(ft^{3})$

Step-by-step explanation:

The composite solid is formed by a cone and a cylinder.

The cone has 16 ft of diameter and its height is 6 ft. Also, its radius is 8 ft (half of the diameter).

The cylinder has 16 ft of diameter and its height is 4 ft. Also, its radius is 8 ft.

Given a cone of radius ''R'' and height ''h'' we can calculate its volume as :

$V(cone)=\pi .R^{2}.\frac{1}{3}.h$ (I)

Given a cylinder of radius ''R'' and height ''h'' we can calculate its volume as :

$V(cylinder)=\pi .R^{2}.h$ (II)

We can calculate the volume of the composite solid as the sum of the volume from the cone and the cylinder ⇒

$V(CompositeSolid)=V(cone)+V(cylinder)$

If we apply (I) and (II) ⇒

$V(CompositeSolid)=\pi .(8ft)^{2}.(\frac{1}{3}).(6ft)+\pi .(8ft)^{2}.(4ft)$

$V(CompositeSolid)=128\pi (ft^{3})+256\pi (ft^{3})$

$V(CompositeSolid)=384\pi (ft^{3})$

$V(CompositeSolid)=1206.4(ft^{3})$

We find that the volume of the composite solid rounded to the nearest tenth is $1206.4(ft^{3})$