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Lilit [14]
3 years ago
9

Explain why mass cannot be used as a property to identify a sample of matter.

Chemistry
1 answer:
Rainbow [258]3 years ago
4 0
Mass cannot be used as a property to identidy a sample of matter because it is an extensive property which depends on the amount of matter in a sample, not the tupe of matter it is.
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Balance this chemical equation. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
larisa86 [58]
The first one have a nice day and good luck
8 0
3 years ago
The maximum efficiency possible in an energy conversion process that is not limited by the second law of thermodynamics
Anna [14]

Answer:

100 %

Explanation:

The maximun efficiency possible (whem not limited by the  second law of thermodynamics) happens when all the energy used is transformed into the type of energy we required with no other transformations.

For example, in an engine we want that all the energy we supply is being converted to work. That's the ideal case, but in reality always some of that energy is lost in the form of heat.

5 0
3 years ago
23) The function of an organelle is related to its
wel

Answer:

Well, it could be B or D but I would say B.

Explanation:

The structure of an organelle is usually fit to its function so it is most likely B.

Hope this helps!

4 0
2 years ago
Read 2 more answers
What is the difference between soluble and insoluble
klemol [59]

Soluble means it can be dissolved

Insoluble means it can't be dissolved

5 0
3 years ago
Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate t
Sedbober [7]

Answer:

Approximately 6.30\times 10^{-3}\;\rm mol.

Explanation:

The gallium here is likely to be produced from a \rm NaGaO_2\, (aq) solution using electrolysis. However, the problem did not provide a chemical equation for that process. How many electrons will it take to produce one mole of gallium?

Note the Roman Numeral "\mathtt{(III)}" next to \rm Ga.  This numeral indicates that the oxidation state of the gallium in this solution is equal to +3. In other words, each gallium atom is three electrons short from being neutral. It would take three electrons to reduce one of these atoms to its neutral, metallic state in the form of \rm Ga\, (s).

As a result, it would take three moles of electrons to deposit one mole of gallium atoms from this gallium \mathtt{(III)} solution.

How many electrons are supplied? Start by finding the charge on all the electrons in the unit coulomb. Make sure all values are in their standard units.

t = \rm 80.0\; min = 80.0\; min \times 60\;s \cdot min^{-1} = 4800\; s.

Q = I \cdot t = \rm 0.380 \; A \times 4800 \; s = 1.824\times 10^3\; C.

Calculate the number of electrons in moles using the Faraday's constant. This constant gives the size of the charge (in coulombs) on each mole of electrons.

\begin{aligned} n(\text{electrons}) &= \frac{Q}{F} \cr &= \rm \dfrac{1.824\times 10^3\; C}{96485.332\; C \cdot mol^{-1}}\cr &\approx \rm 1.89\times 10^{-2}\; mol \end{aligned}.

It takes three moles of electrons to deposit one mole of gallium atoms \rm Ga\, (s). As a result, \rm 1.89\times 10^{-2}\; mol of electrons would deposit \displaystyle \rm \frac{1}{3}\times 1.89\times 10^{-2}\; mol \approx 6.30\times 10^{-3}\; mol of gallium atoms \rm Ga\, (s).

8 0
3 years ago
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