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3 years ago

What is the simplified form of each expression? (2 – 9c)(–8)

1 answer:

4 0

Hi, thank you for posting your question here at Brainly. This is a simple algebra problem. Through the distributive property, simply multiply -8 to each of the terms inside the parenthesis:

2(-8) - 9c(-8)
-16 + 72c

The answer is A.

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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

3 years ago

Write the percent as a fraction or mixed number in simplest form.<br> 12%

Anettt [7]

In order to convert percentage form into fraction, divide it by 100

So, 12% = 12/100 = 6/50 = 3/25

In short, Your Answer would be: 3/25

Hope this helps!

7 0

3 years ago

Read 2 more answers

Keisha has one penny, one nickel, and one dime in her pocket. She randomly takes on coin out of her pocket. Without putting it b

andrezito [222]

There are 12 different ways she could take a penny, a nickle, and a dime out of here pocket and only pick 2. What i did was i took 2 and 3 and multiplied them. because i can pick 2 coins, and there are 3 coins in total. After i multiplied them i got 6, then i got 2 and multiplied it by 6 and came out with 12. The reason why i did that is because there are 6 outcomes so far then you have to multiply them by 2 to get all of your complete outcomes. I hope i could help!!! Please give me brainliest!!! Have a great day =D!!!

3 0

3 years ago

How do you solve k/2+9=30

Mrrafil [7]

If you would like to solve the equation k / 2 + 9 = 30, you can calculate this using the following steps:

k / 2 + 9 = 30
k / 2 = 30 - 9
k / 2 = 21 /*2
k = 21 * 2
k = 42

The result is 42.

4 0

3 years ago

Read 2 more answers

Y is equal to the additive inverse of 4x. Use this information to find the value of the expression 17x + 3y in terms of x.

nevsk [136]

Answer:

Step-by-step explanation:

The additive inverse of a function is that value added that will sum it up to zero

If y is the additive inverse of 4x, then y = -4x

Given the expression 17x+3y

Substitute y = -4x into the expression to have;

17x + 3(-4x)

17x -12x

Hence the value of the expression in terms of x is 5x

5 0

2 years ago