Question

Given p(x)=3x^5+2x^2-5, what is the value of the function at -5/3

Answer 1

Answer:

$-\frac{3080}{81}$

Step-by-step explanation:

The given function is:

$p(x)=3x^{5}+2x^{2}-5$

We have to find the value of the function at x = -5/3

In order to do this we need to replace every occurrence of x in the given function by -5/3. i.e.

$p(-\frac{5}{3})=3(-\frac{5}{3})^{5}+2(-\frac{5}{3} )^{2}-5\\\\ p(-\frac{5}{3})=3(-\frac{3125}{243} )+2(\frac{25}{9} )-5\\\\p(-\frac{5}{3})=-\frac{3125}{81}+\frac{50}{9}-5\\\\ p(-\frac{5}{3})=-\frac{3080}{81}$

Thus, the value of the function at x =-5/3 is $-\frac{3080}{81}$