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Tresset [83]
4 years ago
6

A basketball player made 25 baskets in a season. Of these, 36% were three-point shots. How many three-point shots did he make? A

. 16 B. 11 C. 5 D. 9
Mathematics
1 answer:
denis-greek [22]4 years ago
4 0
<span>36% of 25 baskets were three-point shots
 = 0.36 x 25
= 9

So the correct answer is <u>D. 9</u></span>
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BRAINLIEST FOR WHOEVER ANSWERS FIRST!!!!
Fofino [41]

Answer:

x = 34

Step-by-step explanation:

ΔABD and ΔBCD are both isosceles triangles

In ΔABD

AB =AD, hence ∠ABD = ∠ADB ( base angles are equal )

∠ABD = \frac{180-44}{2} = \frac{136}{2} = 68°

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∠BCD = x = \frac{180-112}{2} = \frac{68}{2} = 34


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What is bigger 5/6 or 7/12
Fynjy0 [20]
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A bag contains red marbles, white marbles, and blue marbles. Randomly choose two marbles, one at a time, and without replacement
dsp73

Answer:

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

P(Same) = \frac{67}{210}

Step-by-step explanation:

Given (Omitted from the question)

Red = 7

White = 9

Blue = 5

Solving (a): P(First\ White\ and\ Second\ Blue)

This is calculated using:

P(First\ White\ and\ Second\ Blue) = P(White) * P(Blue)

P(First\ White\ and\ Second\ Blue) = \frac{n(White)}{Total} * \frac{n(Blue)}{Total - 1}

<em>We used Total - 1 because it is a probability without replacement</em>

So, we have:

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{21 - 1}

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{20}

P(First\ White\ and\ Second\ Blue) = \frac{9*5}{21*20}

P(First\ White\ and\ Second\ Blue) = \frac{45}{420}

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

Solving (b) P(Same)

This is calculated as:

P(Same) = P(First\ Blue\ and Second\ Blue)\or\ P(First\ Red\ and Second\ Red)\ or\ P(First\ White\ and Second\ White)

P(Same) = (\frac{n(Blue)}{Total} * \frac{n(Blue)-1}{Total-1})+(\frac{n(Red)}{Total} * \frac{n(Red)-1}{Total-1})+(\frac{n(White)}{Total} * \frac{n(White)-1}{Total-1})

P(Same) = (\frac{5}{21} * \frac{4}{20})+(\frac{7}{21} * \frac{6}{20})+(\frac{9}{21} * \frac{8}{20})

P(Same) = \frac{20}{420}+\frac{42}{420} +\frac{72}{420}

P(Same) = \frac{20+42+72}{420}

P(Same) = \frac{134}{420}

P(Same) = \frac{67}{210}

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3 years ago
Below, explain why we are allowed the
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Answer:

because in the bottom eqution it shows us x-3=y therefor we could re-write the top equation as x+x-3=11

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