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olya-2409 [2.1K]
3 years ago
10

Write the equation of the line that passes through the points 7.5) and (-6.2). Put

Mathematics
1 answer:
Oksanka [162]3 years ago
8 0

Answer:

is there a line that its perpendicular or parallel to?

Step-by-step explanation:

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What is the volume of the shape?
rodikova [14]

Answer:

volume: 1/3 a²h

= 1/3 ×2²x6

= 8 feet³

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3 years ago
Heights​ (cm) and weights​ (kg) are measured for 100 randomly selected adult​ males, and range from heights of 133 to 193 cm and
yawa3891 [41]

Answer:

The weight of an adult male who is 172 cm tall is 89.36 kg.

Step-by-step explanation:

The regression equation representing the relationship between height and weight of a person is:

\hat y=-105+1.13x

Here

<em>y</em> = weight of a person

<em>x</em> = height of a person

The information provided is:

\bar x=167.90\ cm\\\bar y=81.47\ kg\\r (X, Y) = 0.228\\p-value=0.023\\\alpha =0.05

The hypothesis to test the significance of the correlation between height and weight is:

<em>H₀</em>: There is no relationship between the height and weight, i.e. <em>ρ</em> = 0.

<em>Hₐ</em>: There is a relationship between the height and weight, i.e. <em>ρ </em>≠ 0.

Decision rule:

If the <em>p</em>-value of the test is less than the significance level, then the null hypothesis will be rejected and vice-versa.

According to information provided:

<em>p</em>-value = 0.023 < <em>α</em> = 0.05

The null hypothesis was rejected at 5% level of significance.

Thus, concluding that there is a relationship between the height and weight.

Compute the weight of an adult male with height, <em>x</em> = 172 cm as follows:

\hat y=-105+1.13x

  =-105+(1.13\times 172)\\=-105+194.36\\=89.36

Thus, the weight of an adult male who is 172 cm tall is 89.36 kg.

5 0
3 years ago
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Answer:

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4 0
3 years ago
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Rapper DaBaby drove at a speed of 45 mph in front of Coosa High School on his way home from North Carolina. What was his speed i
NeTakaya
To find the answer, set up an equation:
\frac{45 \: miles}{1 \: hour}  \times  \frac{1000 \: meters}{1 \: mile}  \times  \frac{1 \: hour}{3600 \: seconds}  =
Using this set up we can cross out the units that are on opposite sides of the proportion such as miles and hours, leaving us with the desired units of meters and seconds. Then calculate m/s by multiplying 45 by 1000 meters and then dividing that value by 3600 seconds.

The resulting answer is 45mph = 12.5 m/s
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3 years ago
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If 14 g of a radioactive substance are present initially and 3 yr later only 7 g​ remain, how much of the substance will be pres
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