Answer:
If Thomson's atomic theory was accurate, the positively charged particles would have gone through the foil.
The answer is D. Europa Clipper
Answer:
- <em>The molar solubility is</em> <u>0.0118 mole / liter = 1.18 × 10⁻² M</u>
Explanation:
1) <em><u>Ksp </u></em>stands for product solubility constant.
2) The <u>product solubility constant </u>is the equilibrium constant used for the aqueous ionization (dissolution) of low soluble ionic compounds.
3) The ionization or <u>equilibrium</u> reaction for the PbBr₂ is:
- PbBr₂ (s) ⇄ Pb²⁺ (aq) + 2 Br(aq)⁻
4<u>) Sotichiometry</u>:
- PbBr₂ (s) ⇄ Pb²⁺ (aq) + 2 Br(aq)⁻
Ao - x moles x 2x
5) <u>Calculations</u><u>:</u>
Per definition of Ksp:
- Ksp = [Pb²⁺] [Br(aq)⁻]² = (x) (2x)² = 4x³
- Then, you have to solve: 6.60×10⁻⁶ = 4x³
- x = 0.0118 mole / liter = 1.18 × 10⁻² M
Answer:
Aromatization leads to evolution of carbon dioxide
Explanation:
In p-hydroxybenzoic acid, -OH and -COOH groups remain in para position.
The directing effect of -OH and -COOH group act synergistically to react with three equivalent of bromine.
In para position of -OH group, -COOH remains attached along with a Br atom in a same carbon atom. During aromatization of benzene group, this -COOH group decomposes to give carbon dioxide.
Reaction scheme has been shown below.
