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siniylev [52]
3 years ago
6

Why is water a neutral substance

Chemistry
2 answers:
irina1246 [14]3 years ago
6 0

Answer: Water is considered neutral because the concentration of hydrogen and hydroxide ions is the same

Explanation:

earnstyle [38]3 years ago
4 0

Answer:

Water is considered neutral because the concentration of hydrogen and hydroxide ions is the same.

Explanation:

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Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
love history [14]

Answer:

FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

Explanation:

Empirical formula of ionic compound formed by two ions A^{x+} and B^{y-} is A_{y}B_{x} (for x\neq y) of AB (for x = y)

The above empirical formula is in accordance with charge neutrality principle

Here each cation (Fe^{3+} and Fe^{2+}) can form two ionic compounds by combining with two given anions (SO_{4}^{2-} and CH_{3}CO^{2-}).

So the four ionic compounds are: FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

4 0
3 years ago
Write the balanced reaction and solubility product expression (KSP) for dissolving silver chromate: Ag2CrO4(s). Include all char
Sonbull [250]

Answer:

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓

Ksp = [2s]²  . [s] → 4s³

Explanation:

Ag₂CrO₄ → 2Ag⁺  + CrO₄⁻²

Chromate silver is a ionic salt that can be dissociated. When we have a mixture of both ions, we can produce the salt which is a precipitated.

2Ag⁺ (aq)  + CrO₄⁻² (aq) ⇄  Ag₂CrO₄ (s) ↓ Ksp

That's the expression for the precipitation equilibrium.

To determine the solubility product expression, we work with the Ksp

Ag₂CrO₄ (s)  ⇄ 2Ag⁺ (aq)  + CrO₄⁻² (aq)   Ksp

                          2 s                 s

Look the stoichiometry is 1:2, between the salt and the silver.

Ksp = [2s]²  . [s] → 4s³

 

3 0
3 years ago
What is the concentration of a solution that is 0.25 moles of HCL added to 3.00L of water?
Lina20 [59]

Answer: 0.08 M

Explanation:

\text{molarity}=\frac{\text{moles of solute}}{\text{liters of solution}}\\\\\text{molarity}=\frac{0.25}{3.00}\\\\\text{molarity}=\boxed{0.08 \text{ M}}

3 0
2 years ago
The equation of which of the below scientists could be used to find the wavelength of the emission lines of the hydrogen atom:
mihalych1998 [28]

The equation that scientists could use to find the wavelength of the emission lines of the hydrogen atom would be that of Balmer.

The wavelength of the emission lines of the hydrogen atom can be derived using the Balmer series:

        1/λ  = R_H (1/4 - 1/n^2)

Where λ = wavelength, R_H = Rydberg constant, and n = level of the original orbital.

The equation becomes applicable in getting the wavelength of emitted light when electrons in hydrogen atoms transition from higher (n) orbital to lower orbital (2)  levels.

More on the Balmer series can be found here: brainly.com/question/5295294

3 0
2 years ago
what is meant by a calibration curve for a colored substance being studied with a spectrophotometer? How is a calibration curve
BlackZzzverrR [31]

Answer:

The concentration of the analyte is determined by fitting the absorbance or transmittance obtained by spectrophotometric analysis of the unknown solution into the calibration curve.

Explanation:

In a calibration curve, the instrumental response (absorbance or transmittance), is plotted against the concentration of the analyte (the substance to be measured). The analyst is expected to prepare a series of standard solutions of the analyte within a range of solution concentrations close to the expected concentration of analyte in the unknown solution. The method of least squares may be used to determine the best fit of the line, thus, the concentration of the analyte. This method is only used for the determination of the concentration of coloured substances (spectrophotometry).

3 0
3 years ago
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