Answer:
n=17.85 moles
Explanation:
Given mass is, m = 1.5 kg = 1500 g
The molar mass of sodium bicarbonate is, M = 84.007 g/mol
We need to find the no of moles in 1.5 kg of Sodium bicarbonate . We know that, no of moles is equal to given mass divided by molar mass.
Answer:
Explanation:
Pipet is used to dispense a very small amount of liquid.
Test tube rack is used to hold multiple test tubes at the same time.
Test Table is used to view chemical reactions or hold or heat small amounts of substance.
Scoopula is used to dispense chemicals from a larger container.
Graduated cylinder is used to measure volume very precisely.
Bunsen burner is used to heat objects.
Beaker is used to transport heat or store substance.
Spot plate is used to observe the color changes of small quantities of a reacting mixture.
Goggles are used to protect the eyes from flying objects or chemical splashes.
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Explanation:
The given data is as follows.
[HCOOH] = 0.2 M, [NaOH] = 2.0 M,
V = 500 ml, [Benzoic acid] = 0.2 M
First, we will calculate the number of moles of benzoic acid as follows.
No. of moles of benzoic acid = Molarity × Volume
=
= 0.095 mol
And, moles of NaOH present in the solution will be as follows.
No. of moles of NaOH = Molarity × Volume
=
= 0.05 mol
Hence, the ICE table for the chemical equation will be as follows.
Initial: 0.095 0.05 0 0
Equlbm: (0.095 - 0.05) 0 0.05
pH =
=
= 4.245
For,
Initial: 0.2x 2(0.5 - x) 0
Equlbm: 0.2x - 2(0.5 - x) 0 2(0.5 - x)
As,
pH =
4.245 = 3.75 +
= 0.5
= 3.162
Now,
= 3.162
x = 0.464 L
Volume of NaOH = (0.5 - 0.464) L
= 0.036 L
= 36 ml (as 1 L = 1000 mL)
And, volume of formic acid is 464 mL.