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Rasek [7]
3 years ago
5

How does waer evapourate? one question brainlyist

Chemistry
1 answer:
Ratling [72]3 years ago
4 0

Answer:

water evaportaes from heat it then turns into a gas then can go into a solid one day and repeat the cycle

Explanation:

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A 3.5 gram sample of a radioactive element was formed in a 1960 explosion of an atomic bomb at Johnson Island in the Pacific tes
Annette [7]
The answer is 0.62g.
Solution:
From year 1960 to year 2030, it has been 
     2030-1960 = 70 years

The half-life of the radioactive element is 28 years, then the sample will go through
     70 years * (1 half-life/28 years) = 2.5 half-lives

Starting with a 3.5 gram sample, we will have
     3.5*(1/2) after one half-life passes
     3.5*(1/2) * (1/2) = 3.5*(1/4) after two half-lives pass
     3.5*(1/4) * (1/2) = 3.5*(1/8) after three half-lives pass and so on

Therefore, we can write the remaining amount of the sample after the number n of half-lives have passed as
     mass of sample = initial mass of sample/2^n

The mass of the remaining sample for n = 2.5half-lives can be now calculated as
     mass of sample = 3.5 grams / 2^2.5 = 0.62 g
5 0
3 years ago
A potassium bromide solution is 8.34% potassium bromide by mass and its density is 1.03 g/ml. what mass of potassium bromide is
jenyasd209 [6]

Answer:-  3.84 grams

Solution:-  Volume of the sample is 44.8 mL and the density is 1.03 gram per mL.

From the density and volume we calculate the mass as:

mass = volume*density

44.8mL(\frac{1.03g}{mL})

= 46.1 g

From given info, potassium bromide solution is 8.34% potassium bromide by mass. It means if we have 100 grams of the solution then 8.34 grams of potassium bromide is present in. We need to calculate how many grams of potassium bromide are present in 46.1 grams of the solution.

The calculations could easily be done using dimensional analysis as:

46.1gSolution(\frac{8.34gKBr}{100gSolution})

= 3.84 g KBr

Hence, 3.84 grams of KBr are present in 44.8 mL of the solution.

8 0
4 years ago
Convert 7.2 × 10^23 molecules of CO2 to moles (round to the nearest tenth). <br>Unit?​
Svetach [21]

7.2 * 10^23 molecules CO2           1 mole CO2

                                                 x  ___________________

                                                      6.02* 10^23 molecules CO2

=1.196

=1.2 moles of CO2

5 0
3 years ago
_______at astronomical observatories capture this light even better, providing a clearer picture of our galaxy.
ozzi

Answer:

asrsrhWrrgrefev

Explanation:

  1. DVF HTUKTYGFGZERGQMHMTU6U78O78<u>XCSDBSDBDSVSD∈∈∈∈∈∈∈∵∵∵∵∵∵∵¬¬¬¬¬¬¬¬¬¬¬㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏒㏑㏑㏑㏑㏑㏑㏑㏑㏑㏑㏑㏑㏑㏑㏑㏑㏑㏑∞∞∞∞∞∞∞∞.</u>
6 0
3 years ago
In a laboratory experiment you are given 46.1 grams of MgSO4 and asked to make a 1.20 M solution. The volume of your solution wi
Darina [25.2K]

Answer:

0.319 L

Explanation:

M(MgSO4) = 120 g/mol

46.1 g * 1 mol/120 g = 0.384 mol MgSO4

0.384 mol * 1 L/1.20 mol = 0.319 L

5 0
3 years ago
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