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solmaris [256]
3 years ago
14

What is the net ion equation and spectator ions for the reaction of (aq) NaC2H3O2 and aq (NH4)2 CO3?

Chemistry
1 answer:
mestny [16]3 years ago
4 0

The reaction is:

(C₂H₃O₂)²⁻ +  NH₄⁺ = (NH₄)(C₂H₃O₂).

Na^+  and CO_3^2 - are the spectator ions.

<h3><u>Explanation:</u></h3>

The reactants in the reaction is sodium acetate and ammonium carbonate. They form the soluble molecule sodium carbonate and slightly soluble ammonium acetate. This is a double displacement reaction.

Spectator ions in the reaction are those ions which are present in the reaction but they actually don't take part in the reaction that's happening and they remain same before and after the reaction. In this reaction, the spectator ions are sodium and carbonate which remain in ionized form in the solution before and after the reaction.

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In a 35.0 L tank of N2O3 at STP, how many molecules are there?​
likoan [24]

Answer:

9.40x10^{23}molecules

Explanation:

Hello!

In this case, since we are given the volume of N2O3 and pressure and temperature for the STP (1.00 atm and 273.15 K), we can compute the moles, considering the ideal gas equation as shown below:

PV=nRT\\\\n=\frac{PV}{RT} \\\\n=\frac{1atm*35L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n=1.56mol

Now, by using the Avogadro's number it is possible to compute the molecules of this case in 1.56 moles:

molecules=1.56mol*\frac{6.022x10^{23}}{1mol} =9.40x10^{23}molecules

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3 years ago
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Answer:

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7 0
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Explanation:

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