Cross-platform.
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<span>B. Efficiency
(</span><span>effective training </span><span>techniques)</span>
Answer:
Latency of an object O is shown below.
Explanation:
W segment and stalled state transmits nothing and waits for acknowledgement. The latency is 2 R TT + the time required for server that are using to transmit the object + the amount of time when server is in stalled state. Let K be the number of window that is K= O/WS .The serveries stalled state where K-1 is period of ime with period lasting RTT-(W-1)S/R
latency = 2RTT +O/R +(K-1)[S/R +RTT - WS/R]
After combining the two case
latency = 2 RTT + O/R + (K-1)[S/R +RTT - WS/R]
where [x] means maximum of (x.0). This is the complete ananlysis of the static windows.
server time for transmit the object is (K-1)[S/R +RTT - WS/R]
With four processing cores, we get a speedup of 1.82 times.
<h3>
What is Amdahl's Law?</h3>
Amdahl's law exists as a formula that provides the theoretical speedup in latency of the implementation of a task at a fixed workload that can be expected of a system whose resources exist improved.
Amdahl's law exists that, in a program with parallel processing, a relatively few instructions that hold to be completed in sequence will have a limiting factor on program speedup such that adding more processors may not complete the program run faster.
Amdahl's law stands also known as Amdahl's argument. It is utilized to find the maximum expected progress to an overall system when only part of the system exists improved. It is often utilized in parallel computing to indicate the theoretical maximum speed up utilizing multiple processors.
Hence, With four processing cores, we get a speedup of 1.82 times.
To learn more about Amdahl's Law refer to:
brainly.com/question/16857455
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