Yes. You can find that out by multiplying .1 by 274. It equals 27.4.
Answer:
(the statement does not appear to be true)
Step-by-step explanation:
I don't think the statement is true, but you CAN compute the intercepted arc from the angle.
Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.
Therefore, adding the angles together, we have:
alpha + 90 + 90 + <FDG = 360
Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)
Hello.
We have:
- A point that the line passes through
- The slope of the line
Plug the values into the Point-Slope Formula:





I hope it helps.
Have a nice day.

Answer:
True
Step-by-step explanation:
- They both have a 90 degree angle
- 90+38=128
- 180-128=52
- The triangles are similar by AAA(Angle Angle Angle)
The answer should be x=60. ABD are an equilateral triangle all the angles must add up to 180. 60*3=180. Also if you have a protractor you can measure the angle C, the 60 degrees part and measure it against A, D and B. Hope this helps.