Question

An FM radio station broadcasts at 84 megahertz (MHz). What is the energy of each photon in Joule? Use h = 6.6 * 10 ^ (- 34) * j * s for the Planck constant

Answer 1

Answer:

$E=5.544*10^{-26} J$

Step-by-step explanation:

The equation for photon energy is given by:

$E=hf$

Where:

$h=Planck\hspace{3}constant=6.6*10^{-34} \\f=Frequency\hspace{3}of\hspace{3}the\hspace{3}wave=84000000Hz$

This equation telling us that the higher the frequency of the photon, the greater its energy. And the longer the photon wavelength, the lower its energy.

So, replacing the data provided in the previous equation:

$E=(6.6*10^{-34} )*(84000000)=5.544*10^{-26} J$