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mafiozo [28]
3 years ago
9

a block is dragged without acceleration in a straight-line path across a level surface by a force of 6N. what is the frictional

force between the block and the surface?
Physics
1 answer:
Maurinko [17]3 years ago
3 0

The frictional force between the block and the surface is 6 N

Explanation:

We can solve this problem by applying Newton's second law of motion, which states that the net force on an object is equal to the product between its mass and its acceleration:

F_{net}=ma

where

F_{net} is the net force

m is the mass

a is the acceleration

For the block in this problem, we have:

a=0, because its acceleration is zero

F_{net}=F_a-F_f, since the net force is given by the difference between the applied force F_a (in the forward direction) and the frictional force F_f (in the backward direction)

Therefore Newton's second law becomes

F_a-F_f = ma = 0

Which means

F_f=F_a

And since the applied force is F_a=6 N, this means that the friction force is also 6 N:

F_f=F_a=6 N

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

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A box is being pulled to the right over a rough surface. t > fk , so the box is speeding up. Suddenly the rope breaks. What h
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Answer:

a. keeps its speed for a short while, then slows and stops. slows steadily until it stops.

Explanation:

Since the tension in the rope, t is greater than the kinetic friction fk, the box is moving forward because there is a net force on it. That is, t - fk = f = ma.

Since there is a net force, there is an acceleration and thus an increasing velocity.

When the rope breaks, the tension, t = 0. So, t - fk = 0 - fk = -fk = ma'.

Now, the net force acting on the box is friction in the opposite direction. This force tends to slow the box down from its initial velocity at acceleration, 'a' until its velocity is zero, where it stops. Since the frictional force is constant, the acceleration, a' on the box is thus constant and the box undergoes uniform deceleration until its velocity is zero.

<u>So, the box keeps its speed for a short while, then slows and stops. slows steadily until it stops.</u>

So, the answer is a.

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3 years ago
An ideal gas is brought through an isothermal compression process. The 5.00 mol of gas goes from an initial volume of 216.5×10−6
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Explanation:

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3 years ago
This multiple-concept example provides a review of the concepts that play roles here. An engine has an efficiency of 63% and pro
frozen [14]

Answer:

8387 J

Explanation:

work produced= 5284 J

efficiency of 63%

the efficiency η= Work done÷ heat supplied

\eta= \frac{W}{Q_s}

0.63= \frac{5284}{Q_s}

solving Q_s= 8397 J

therefore,  the input heat=  8387 J

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3 years ago
The electric field of a sinusoidal electromagnetic wave obeys the equation E = (375V /m) cos[(1.99× 107rad/m)x + (5.97 × 1015rad
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Answer:

a)  v = 2,9992 10⁸ m / s , b)  Eo = 375 V / m ,  B = 1.25 10⁻⁶ T,

c)     λ = 3,157 10⁻⁷ m,   f = 9.50 10¹⁴ Hz ,  T = 1.05 10⁻¹⁵ s , UV

Explanation:

In this problem they give us the equation of the traveling wave

        E = 375 cos [1.99 10⁷ x + 5.97 10¹⁵ t]

a) what the wave velocity

all waves must meet

        v = λ f

In this case, because of an electromagnetic wave, the speed must be the speed of light.

        k = 2π / λ

        λ = 2π / k

        λ = 2π / 1.99 10⁷

        λ = 3,157 10⁻⁷ m

        w = 2π f

        f = w / 2 π

        f = 5.97 10¹⁵ / 2π

        f = 9.50 10¹⁴ Hz

the wave speed is

        v = 3,157 10⁻⁷   9.50 10¹⁴

        v = 2,9992 10⁸ m / s

b) The electric field is

           Eo = 375 V / m

to find the magnetic field we use

           E / B = c

           B = E / c

            B = 375 / 2,9992 10⁸

            B = 1.25 10⁻⁶ T

c) The period is

           T = 1 / f

            T = 1 / 9.50 10¹⁴

            T = 1.05 10⁻¹⁵ s

the wavelength value is

          λ = 3,157 10-7 m (109 nm / 1m) = 315.7 nm

this wavelength corresponds to the ultraviolet

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