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kati45 [8]
3 years ago
7

What is the mass of a stone moving at a speed of

Physics
2 answers:
Serhud [2]3 years ago
6 0
P = m*v 7.5 = m*15 m = 7.5/15 = 0.5 kg
Dovator [93]3 years ago
6 0

Answer: A 0.5kg

Explanation:

Momentum is defined as the product of mass and velocity of a body.

Momentum = mass × velocity

Mass = ?

Momentum = 7.5kgm/s

Velocity = 15m/s

Mass = Momentum/Velocity

Mass = 7.5/15

Mass = 0.5kg

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Plz help me!!!! A spring is connected to a wall as shown below. A mass on a horizontal surface is connected to the springs and p
kirill [66]

Answer:

320 N/m

Explanation:

F = k·Δx

where

F is the restoring force of the spring

k is the proportionality constant called the ‘spring constant’

Δx is the change in the spring’s position due to the deformation.

You need the k so

25 cm= 0.25m

k=F/∆x = 80/0.25 = 320 N/m

6 0
3 years ago
In the circuit shown below, 0.25 A of current flows through a 20-Ω resistor. How much voltage is needed to produce this current?
balu736 [363]

Answer:

D 5 V

Explanation:

Without seeing the whole circuit it is impossible to say for certain.

However the simplest circuit would produce a value of

FV = IR = 0.25(20) = 5 v

5 0
3 years ago
What happens to the chemical structure of water when it changes state?
Marta_Voda [28]

Answer:

c) Water molecules melt into gas molecules.

5 0
3 years ago
Which statement is true about an object that sinks in water?
Rina8888 [55]
A > Is the correct answer :)
5 0
3 years ago
Read 2 more answers
A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.8 1010 m (inside the orbit
creativ13 [48]

Answer:

Explanation:

From the given information:

Distance d_i = 4.8 \times 10^{10} \ m

Speed of the comet V_i = 9.1 \times 10^{4} \ m/s

At distance d_2 = 6 \times 10^{12} \ m

where;

mass of the sun = 1.98 \times 10^{30}

G = 6.67 \times 10^{-11}

To find the speed V_f:

Using the formula:

E_f = E_i + W \\ \\  where; \  \  W = 0  \ \  \text{since work done by surrounding is zero (0)}

E_f = E_i + 0 \\ \\  K_f + U_f = K_i + U_i  \\ \\ = \dfrac{1}{2}mV_f^2 +  \dfrac{-GMm}{d^2} =  \dfrac{1}{2}mV_i^2+ \dfrac{-GMm}{d_i} \\ \\ V_f = \sqrt{V_i^2 + 2 GM \Big [  \dfrac{1}{d_2}- \dfrac{1}{d_i}\Big ]}

V_f = \sqrt{(9.1 \times 10^{4})^2 + 2 (6.67\times 10^{-11}) *(1.98 * 10^{30} ) \Big [  \dfrac{1}{6*10^{12}}- \dfrac{1}{4.8*10^{10}}\Big ]}

\mathbf{V_f =53.125 \times 10^4 \ m/s}

3 0
3 years ago
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