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algol13
3 years ago
5

Andy has been working at Aerial Corp. for a long time. He feels he is hard working and that he deserves a pay hike. He seeks a m

eeting with Anna, his manager, to ask for a raise. As Anna is busy preparing for the annual board meeting, Andy decides to postpone the meeting with Anna. In this scenario, which of the following dimensions of context influenced Andy's interaction with Anna?A) ​The physical context
B) ​The social context
C) ​The chronological context
D) ​The cultural context
Business
2 answers:
Norma-Jean [14]3 years ago
4 0

Answer:

C) ​The chronological context

Explanation:

Chronological context refers to time related factors that affects affects communication. The effect could be favourable or unfavourable.

In this scenario because Andy had worked for a long time and he feels he is hard working, he feels he deserves a pay raise.

His need for a pay raise is time based. It is initiated by his length of service in the company. So this is a chronological context in which a time based factor affects communication between Andy and Anna.

suter [353]3 years ago
4 0

Answer: The answer is C. The chronological context.

Explanation:

The chronological context of interaction is simply used to describe the time related factors that could influence communication between individuals or companies.

This context takes into consideration, the time that a particular communication process is initiated.

For instance, is a particular communication process initiated during or after work hours? Is it made at a time when the company is going through major issues like a strike, or major losses?

From the scenario given above, we cab see that Andy decided to postpone his meeting with Anna, because the timing was not right, due to the fact that Anna was busy preparing for the annual board meeting.

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Mateo exchanges a rental house at the beach with an adjusted basis of $225,000 and a fair market value of $200,000 for a rental
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Answer:

B

Explanation:

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3 years ago
What is a task force? Group of answer choices a formal group whose members must be able to perform all tasks of the team a forma
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A temporary team formed to solve a problem, realize an opportunity, or design a product or service.

<h3>What is a task force?</h3>
  • A task force is a team of individuals who have been given the temporary assignment to collaborate in order to accomplish a very specific and well-defined goal.
  • A temporary team formed to solve a problem, realize an opportunity, or design a product or service. 
  • For instance, a drug task force operates separately from a police force to deal with concerns pertaining to the production, distribution, and use of illicit narcotics.
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  • Collaboration is the process of two or more parties cooperating to carry out a task or realize an objective.
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  • Leadership is a necessary component of most collaborations, albeit it can take the form of social leadership within an egalitarian, decentralized group.

Therefore, the task force is a temporary team formed to solve a problem, realize an opportunity, or design a product or service.

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3 0
1 year ago
Which of the following is not a part of budgeting?
vodomira [7]
The last one seems just right as it doesn’t fit into the budget industry
6 0
3 years ago
Which of the following is (are) correct concerning the parties of a trust deed?1. The trustee has naked title2. The lender is na
svlad2 [7]

Answer:

  1. The trustee has naked title
  2. The lender is named the beneficiary
  3. The trustor has legal title

Explanation:

A Trust deed is a legal agreement that allows for a debtor to transfer ownership of a physical real estate property to a Trustee so that that trustee may hold the property as security for a loan transaction involving the lender and the debtor.

The trustee in this agreement holds a naked title which is a legal title to a property that is given to a trustee as it has no ownership benefits. The beneficiary is also named to be the lender and the Trustor retains the legal title.

5 0
3 years ago
Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Sonbull [250]

Answer:

Mean = 47

Median = 47.38

Standard Deviation = 12.73

Explanation:

Note: You wrote " 40 manufacturing companies, but the total number of companies you actually listed is 75, definitely you meant 75.

Let y represent the range of advertising expenditure, f represent the number of companies, x represent the midpoint of the range of advertising expenditure.

y                                       f                      x                  fx                    fx²

$20 to under $30            9                     25               225               5625

$30 to under $40            13                    35               455               15925

$40 to under $50            21                    45               945              42525

$50 to under $60            18                    55               990              54450

$60 to under $70            14                     65               910               59150

                                       n = 75                           \sum fx = 3525      

\sum fx^2 = 177675

Mean, \bar{X} = \frac{\sum fx}{n}

\bar{X} = \frac{3525}{75} \\\bar{X} = 47

Standard Deviation:

SD = \sqrt{\frac{n \sum fx^2 - (\sum fx)^2}{n(n-1)} } \\SD = \sqrt{\frac{(75*177675) - (3525)^2}{75(75-1)} }\\SD = 12.73

Median:

Get the cumulative frequencies(cf)

         y                                        f                                cf

$20 to under $30                     9                                9

$30 to under $40                     13                               22

$40 to under $50                     21                               43

$50 to under $60                     18                               61

$60 to under $70                      14                              75

                                                N = 75

Median = Size of (N/2)th item

Median = Size of (75/2)th item

Median = Size of (37.5)th item

The median class = 40 to under 50

Lower limit, L₁ = 40

Cumulative frequency, cf = 22

f = 21

Class Width, h = 10

Median = L_1 + \frac{ (N/2) - cf}{f} * h\\

Median = 40 + \frac{ (75/2) - 22}{21} * 10\\

Median = 47.38

8 0
3 years ago
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