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MatroZZZ [7]
3 years ago
14

Evaluate the expression if m = 3. 3m^2 (SHOW YOUR WORK)

Mathematics
1 answer:
iragen [17]3 years ago
5 0

The value of given expression when m = 3 is 27

<h3><u>Solution:</u></h3>

Given expression is 3m^2

We have to evaluate the given expression for m = 3

To find for m is equal to 3, substitute m = 3 in given expression

From given expression,

\rightarrow 3m^2

Plug in m = 3 in above expression

\rightarrow 3(3)^2 ------ eqn 1

We know that,

a^2 can be expanded as,

a^2=a \times a

Applying this in eqn 1, we get

\rightarrow 3(3)^2=3 \times (3 \times 3)

Simplify the above expression

\rightarrow 3(3)^2=3 \times (3 \times 3) = 3 \times 9 = 27

Therefore, for m = 3 we get,

\rightarrow 3(3)^2=27

Thus value of given expression when m = 3 is found

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ioda

If you just type that exact equation into a calculator it gives you the same answer as well

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2 years ago
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Robert wants to put lights around the edge of his deck. The deck is 46 feet long and 23 feet wide. How many yards of lights does
Korolek [52]
46 yards is the answer

5 0
2 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
2 years ago
Find the lateral area of the cone. radius 32 height 25
padilas [110]

Answer:

<h3>200201+1918191=9191919289+</h3>

Step-by-step explanation:

<h3>tnks </h3>

4 0
2 years ago
6 4/5 - 2 1/5 is what?
pogonyaev
6-2=4     whole number
4/5-1/5=3/5 fraction
  put the fraction and whole number toger and you'll get
since the denominator is the same it's easier to subract

4 3/5    <--- answer
3 0
3 years ago
Read 2 more answers
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