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Murljashka [212]
2 years ago
14

Anna can buy 3 sweaters for the total of $45.00 how much would it cost for her to buy 5 sweaters

Mathematics
2 answers:
Furkat [3]2 years ago
8 0

Answer:

$75.00

Step-by-step explanation:

First divide:

45 ÷ 3 = $15

$15 × 5 = $75.00

Akimi4 [234]2 years ago
5 0

Answer:

75

Step-by-step explanation:

you divide the amount of money by the amount if sweaters,

45/3=15

you then multiply 15*5=75

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Answer:

Step-by-step explanation:

given,

a) √x + 6 = 4                                                    

to solve the above equation subtract both side with 6

    √x + 6 - 6  = 4 - 6                  

                √x  = -2                  

squaring both side

                (√x)² = (-2)²              

                       x = 4            

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to solve the above equation subtract both side with 6

    ∛x + 6 - 6  = 4 - 6

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cubing  both side

                (√x)³ = (-2)³

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3 years ago
Name the subsets of the real numbers to which each number belongs. The square root of 11
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Well the answer for the square root of 11

irrational number

and real number


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Solve the proportion: 12/R = 5/60
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I was to tired to write it down

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Now Cathy is three times as old as Katie. In six years Cathy will be only twice as old as Katie. How old is each girl now?
BabaBlast [244]
Katie is 6; Cathy is 18!

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In 6 years, Katie is 12 and Cathy is 24.

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3 years ago
Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
2 years ago
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