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3 years ago

-2/3(3x-9) = 15 please help

1 answer:

6 0

Your answer would be x=-10.5

First distribute -2/3 to 3x and -9
-2x+6=15
Then subtract 6 from both sides
-2x=9
Divide both sides by -2
x=-4.5

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Which numbers are irrational? Select all that apply.<br> A. 100<br> B. 36<br> C. 27<br> D. 47

vovikov84 [41]

Answer:

none

Step-by-step explanation:

All are rational numbers because each number can be expressed as the quotient of 2 integers:

100÷1

36÷1

27÷1

47÷1

4 0

3 years ago

Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

6 0

2 years ago

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andrew11 [14]

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5 0

3 years ago

Read 2 more answers

What is the range and domain of the function : y= sqrt(x) -5 ... Can you please explain? Thanks btw the square root is only over

Likurg_2 [28]

Okay so basically domain =input and range =output. you can never have a negative number underneath the square root sign because it will make the answer imaginary (i), unless you are on that concept. Therefore the range is any number greater than 0. -> all real numbers greater than or = 0

for the range if you input 0 as x you will get -5, so any number you input after 0 will be greater than -5. so range is all real numbers greater than or equal to -5.

3 0

4 years ago

Read 2 more answers

If P the incenter of triangle JKL, find MP.

hram777 [196]

9514 1404 393

Answer:

MP = 38

Step-by-step explanation:

Each of the lengths MP, NP, OP is the radius of the incircle, so they are all congruent.

3x +14 = 9x -34

48 = 6x . . . . . . . . . . . . . . add 34-3x to both sides

24 = 3x . . . . . . . . . . . . . . divide by 2 (we don't need x; we need 3x or 9x)

NP = 3x +14 = 24 +14 = 38

NP = OP = MP = 38

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3 years ago