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3 years ago

What is the equation for a sine function graph with a period of 2 and an amplitude of 2

Mathematics

2 answers:

postnew [5]3 years ago

4 0

Answer:

y=2sinπx

Step-by-step explanation:

Correct Answer on Edge 2020

jonny [76]3 years ago

3 0

period = 2, Amplitude = 2

AMPLITUDE

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f(t) = sin(t) , this function has an amplitude of 1 , because its y values goes one unit up, and one unit down from the x axis. to increase this to an amplitude of 2, we get f(t) = 2. sin(t). This means the graph is twice as tall as our original function f(t) = 1.sin(t).

PERIOD

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the period has a formula: w = 2pi / |B | . The normal period for a sinewave

f(t) = sin(t) = 2 pi.

So in our new function f(t) = 2 sin (t) [ amplitude is now multiplied by 2], the period (as stated in the question) is 2, that is 2 pi (remember the formula for period stated 2pi) divided by b, which is now 2. Which means 2pi is now divided by 2 or multiplied by 1/2. 2pi /2 = pi or 1/2 x 2pi = pi. so as you increase the period in the equation, the sinewave becomes shorter.

ANSWER

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So the function is actually f(t) = 2.sin(2t).

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A(n - 3) +8= bn for n please help me

Papessa [141]

Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

An -3A +8-An= bn-An.

-3A +8 = bn - An.

We can see n is a common factor on rigth side in bn-an.

Factoring out n on right side from bn-an.

-3A +8 = (b - A)n.

Dividing both sides by (b-A),

$\frac{(-3A+8)}{(b-A)} = \frac{(b-A)n}{(b-A)}$

On right (b-A) paranthiss cancelled and we get n on right side.

$\frac{(-3A+8)}{(b-A)} =n$ Final answer.

So, that would be our final answer

n = (-3A+8)/(b-A)

7 0

3 years ago

Doña Gertrudis recolecta en promedio 75 litros de leche de cabra por día y utiliza alrededor de 5 litros para hacer un kilogramo

Nimfa-mama [501]

Answer:

825 pesos a day on average

1 dozen weight = 2.4 kg

Step-by-step explanation:

In ENGLISH:

Doña Gertrudis collects on average 75 liters of goat milk per day and uses around 5 liters to make one kilogram of cheese. The cheeses he makes weigh 200 grams each and he sells them for 132 pesos a dozen. How much money do you get per day on average from the sale of your cheeses? How many kilograms does the dozen cheeses weigh?

Solution:

75 Liters / 5 Liters = 15

15 * 1 kg = 15 kg of cheese per day

15kg in grams is 15*1000 = 15,000 grams

Each cheese block is 200 grams, so number of blocks of cheese:

15,000/200 = 75 blocks of cheese

1 dozen (12) = 132 pesos, so 1 would be:

132/12 = 11 pesos PER BLOCK

SO, 75 blocks of cheese = 75 * 11 = 825 pesos (per day on average)

Dozen cheese weight in kg,

200 grams * 12 = 2400 grams

In kg,

2400/1000 = 2.4 kg

8 0

3 years ago

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nikdorinn [45]

Answer:

3 $\sqrt{5}$ which is approx 6.71

Step-by-step explanation:

$\sqrt{45}$ = $\sqrt{9}$ · $\sqrt{5}$ = 3 $\sqrt{5}$

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2 years ago

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jekas [21]

Answer: answer is $33.60

Step-by-step explanation:

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