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2 years ago

What is the equation for a sine function graph with a period of 2 and an amplitude of 2

Mathematics

2 answers:

postnew [5]2 years ago

4 0

Answer:

y=2sinπx

Step-by-step explanation:

Correct Answer on Edge 2020

jonny [76]2 years ago

3 0

period = 2, Amplitude = 2

AMPLITUDE

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f(t) = sin(t) , this function has an amplitude of 1 , because its y values goes one unit up, and one unit down from the x axis. to increase this to an amplitude of 2, we get f(t) = 2. sin(t). This means the graph is twice as tall as our original function f(t) = 1.sin(t).

PERIOD

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the period has a formula: w = 2pi / |B | . The normal period for a sinewave

f(t) = sin(t) = 2 pi.

So in our new function f(t) = 2 sin (t) [ amplitude is now multiplied by 2], the period (as stated in the question) is 2, that is 2 pi (remember the formula for period stated 2pi) divided by b, which is now 2. Which means 2pi is now divided by 2 or multiplied by 1/2. 2pi /2 = pi or 1/2 x 2pi = pi. so as you increase the period in the equation, the sinewave becomes shorter.

ANSWER

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So the function is actually f(t) = 2.sin(2t).

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Step-by-step explanation:

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2 years ago

Read 2 more answers

If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$