Change the underlined words if it is not correct and write true if it is correct.
<h3>Integers</h3>
<u>1.</u><u> </u><u>P</u><u>ositive</u> integers are not whole numbers.
Negative integers are not whole numbers.
2. All whole numbers are <u>integers</u>.
True
3. <u>Zero</u> is the smallest whole number.
True
4. Any whole number greater than <u>zero</u> is a positive integers.
True
5. Fractions and Decimals are not integer.
6. 1 is a counting number and a positive integers.
True
7. Rational number include all integers , fraction, or terminating decimals.
True
8. Any whole number that is <u>greater</u> than 0 is a negative integers.
- Any whole number that is <u>less</u> than 0 is a negative integers.
Learn more about integers:
brainly.com/question/10853762
If a triangle has side lengths 5, 5, and 8, then the triangle should be classified as isosceles.
This is because an isosceles triangle has two sides of the same length and one side of a different length. This isn’t an equilateral triangle (where all sides are of equal length) or a scalene triangle (where all sides are of different lengths).
Hope this helps!
Answer:
Rule:

Step-by-step explanation:
<em>I will answer generally, since the coordinates of f, g and h are not given</em>
Given
Point: x, y
Translation Rule
1 : x + 3, y - 1
2: 90 degree counterclockwise
Required
Determine the new coordinates
<u>At the first translation of (x,y) by x + 3, y - 1</u>
The new point is: 
<u>At the second translation (90 degrees counterclockwise)</u>
When a point (x,y) is translated using this rule, it becomes (-y,x)
So, the new point is:


If the initial point of h is (2,3),
The new point is:


Answer: 9.5
Step-by-step explanation:
Answer: 
<u>Step-by-step explanation:</u>
Convert everything to "sin" and "cos" and then cancel out the common factors.
![\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)](https://tex.z-dn.net/?f=%5Cdfrac%7Bcot%28x%29%2Bcsc%28x%29%7D%7Bsin%28x%29%2Btan%28x%29%7D%5C%5C%5C%5C%5C%5C%5Cbigg%28%5Cdfrac%7Bcos%28x%29%7D%7Bsin%28x%29%7D%2B%5Cdfrac%7B1%7D%7Bsin%28x%29%7D%5Cbigg%29%5Cdiv%5Cbigg%28%5Cdfrac%7Bsin%28x%29%7D%7B1%7D%2B%5Cdfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%5Cbigg%29%5C%5C%5C%5C%5C%5C%5Cbigg%28%5Cdfrac%7Bcos%28x%29%7D%7Bsin%28x%29%7D%2B%5Cdfrac%7B1%7D%7Bsin%28x%29%7D%5Cbigg%29%5Cdiv%5Cbigg%5B%5Cdfrac%7Bsin%28x%29%7D%7B1%7D%5Cbigg%28%5Cdfrac%7Bcos%28x%29%7D%7Bcos%28x%29%7D%5Cbigg%29%2B%5Cdfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%5Cbigg%5D%5C%5C%5C%5C%5C%5C%5Cbigg%28%5Cdfrac%7Bcos%28x%29%7D%7Bsin%28x%29%7D%2B%5Cdfrac%7B1%7D%7Bsin%28x%29%7D%5Cbigg%29%5Cdiv%5Cbigg%28%5Cdfrac%7Bsin%28x%29cos%28x%29%7D%7Bcos%28x%29%7D%2B%5Cdfrac%7Bsin%28x%29%7D%7Bcos%28x%29%7D%5Cbigg%29)

