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Tomtit [17]
3 years ago
14

What is 452 to the nearest thousand

Mathematics
2 answers:
Alex73 [517]3 years ago
6 0
0 because 452 does not round to any thousands
son4ous [18]3 years ago
5 0
The next larger even thousand is  1,000 .

The next smaller even thousand is zero thousands.

452  is nearer to <em>zero</em> thousand than it is to  1,000 .
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Write the first five terms of the arithmetic sequence. a4 = 22, a10 = 64
dedylja [7]
Hello :
the general term is : 
an = a1+(n-1)×d  
or : an = ap +(n-p)×d......d is common diffrence
let : n=10 and p= 4
a10 =  a4 +(10-4)×d
64 = 22 + 6d
6d =  42
d= 7
conclusion :
a4 = 22
a3 = 22-7=15
a2=15-7=8
a1= 8-7=1
<span>the first five terms : 1 , 8 , 15 , 22</span>

4 0
3 years ago
Question 2 (1 point)
bekas [8.4K]

Answer:

A. 48

Step-by-step explanation:

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NISA [10]
Answer: 10 meters

Explanation:

29 cm : blank meters

So how do we get from 348 cm to 29 cm?

To figure this out we divide.

348 divided by 28 = 12

we divided by 12 so we do the same with 120

120 divided by 12 = 10

So that’s the answer.

I hope this makes sense and helps you :)
6 0
3 years ago
The graph of linear function f passes through the point (1, −9) and has a slope of −3. What is the zero of f?
ale4655 [162]
Zero of (f) equals -6
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Imagine a pond. In it sits one lilypad, which reproduces once a day. Each of its offspring also reproduces once a day, doubling
sergeinik [125]

Answer: On the 29th day

Step-by-step explanation:

According to this problem, no lilypad dies and the lilypads always reproduce, so we can apply the following reasoning.

On the first day there is only 1 lilypad in the pond. On the second day, the lilypad from the first reproduces, so there are 2 lilypads. On day 3, the 2 lilypads from the second day reproduce, so there are 2×2=4 lilypads. Similarly, on day 4 there are 8 lilypads. Following this pattern, on day 30 there are 2×N lilypads, where N is the number of lilypads on day 29.

The pond is full on the 30th day, when there are 2×N lilypads, so it is half-full when it has N lilypads, that is, on the 29th day. Actually, there are 2^{30} lilypads on the 30th, and 2^{29} lilypads on the 29th. This can be deduced multiplying succesively by 2.  

4 0
3 years ago
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