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Oksana_A [137]
3 years ago
8

Find the quotient when x2 + 10x + 21 is divided by x + 7

Mathematics
1 answer:
Alja [10]3 years ago
5 0

Answer:

The quotient is x+3

Step-by-step explanation:

We first use the remainder theorem to determine whether x+7 is divisible by

x^2+10x+21:

(-7)^2+10(-7)+21\\ = 49 - 70+21 = 0

the remainder is zero which means x^2+10x+21 is divisible by x+7.

Now, we could do polynomial long division to find the quotient, but in this case, it turns out that guessing is easier.

x^2+10x+21

is factored as

x^2+10x+21 = (x+7)(x+3)

which means

\dfrac{x^2+10x+21}{x+7} =(x+3)

which means the quotient is x+3.

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